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3 years ago

I need help with these 2 questions i don’t understand!

Mathematics

2 answers:

Serhud [2]3 years ago

8 0

1: Answer 206 ft.

2: Answer 53 Degrees

Gre4nikov [31]3 years ago

6 0

Wouldn't you use sin, cos, tan?

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Answer the question below

lys-0071 [83]

Answer:

A) -1

Step-by-step explanation:

$\frac{3 + 2\sqrt{5} }{2\sqrt{5}-3 } \\$

We can rewrite 2√5 - 3 as -(3 + 2√5)

Therefore,

$\frac{3+ 2\sqrt{5} }{-(3 + 2\sqrt{5} )} \\$

We can cancel out 3 + 2√5 both in the numerator and the denominator. So we get

= 1/-1

= -1

Answer : A) -1

Thank you.

6 0

3 years ago

4(2x + 3) ÷ 5y From the expression above, provide an example of each of the following: sum, term, product, factor, quotient, and

Ann [662]

Answer:

Sum - 2x + 3

term - 2x

Product - 4(2x + 3)

Factor - not present

quotient - (2x + 3) / 5

Coeffecient - 4(2x + 3)

I really hope this helps

6 0

3 years ago

Read 2 more answers

Simply the following expression: 8x + 5y - 4z + 9y - 3x + 13z

oksian1 [2.3K]

Answer:

5x+14y+9z

Step-by-step explanation:

combine 8x and -3x to get 5x

combine 5y and 9y to get 13y

combine -4z and 13z to get 9z

7 0

2 years ago

Ava buys a used car that costs $6,700.00. She trades in her old car for $3,995.00. How much does she pay in cash for the car?

irakobra [83]

So this statement is caused for subtracting. So we have to subtract 6,700.00 from 3,995.00 and the answer would be 2705
Hope this helps :)

4 0

3 years ago

a major metroplitan newspaper selected a simple random sample of 1,600 readers from their list of 100,000 subscribers. they aske

Arisa [49]

Answer:

The 99% confidence interval for the proportion of readers who would like more coverage of local news is (0.3685, 0.4315).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 1600, \pi = 0.4$

99% confidence level

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4 - 2.575\sqrt{\frac{0.4*0.6}{1600}} = 0.3685$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4 + 2.575\sqrt{\frac{0.4*0.6}{1600}} = 0.4315$

The 99% confidence interval for the proportion of readers who would like more coverage of local news is (0.3685, 0.4315).

7 0

3 years ago