2 years ago

Are the following figures similar?

Mathematics

1 answer:

Svet_ta [14]2 years ago

4 0

Answer:

yes they are, one is just bigger and one is smaller in size!

Step-by-step explanation:

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Allushta [10]

Answer:

$P = 2x+2y$ (1)

And we know that the lenght is y = 20.3. If we solve for x from equation (1) we got:

$P-2y = 2x$

$\frac{P-2y}{2} =x$

And replacing we got:

$x = \frac{72.2 in -2*20.3 in}{2}= 15.8 in$

And the width for this case would be 15.8 in

Step-by-step explanation:

For this case we know that the photo is rectangular. Let's define:

x = the width, y= the length

And we know that the perimeter is given by:

$P = 2x+2y$ (1)

And we know that the lenght is y = 20.3. If we solve for x from equation (1) we got:

$P-2y = 2x$

$\frac{P-2y}{2} =x$

And replacing we got:

$x = \frac{72.2 in -2*20.3 in}{2}= 15.8 in$

And the width for this case would be 15.8 in

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ch4aika [34]

Answer:

i believe 1/5

Step-by-step explanation:

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