According to the given statement, we can get the equation:
50 - 3x = 1/2 (50-x)
where x = amount removed from bag two, 3x removed from bag one
Then we multiply both sides by 2 (to eliminate the ½)
100-6x= 50-x
Add 6x to both sides
100= 50-5x
Then subtract 50 from both sides
50=5x
Lastly, divide by 5
10=x
Therefore 10 kg of sugar was removed from bag 2
further, 3x= 30, so 30 kg of sugar was removed from bag 1.
50-30=20 kg remaining in bag 1.
<span>50-10=40 kg remaining in bag 2.</span>
Answer:
![\begin{gathered} y=\frac{9}{6}x-9 \\ l=\frac{P}{2}-w \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20y%3D%5Cfrac%7B9%7D%7B6%7Dx-9%20%5C%5C%20l%3D%5Cfrac%7BP%7D%7B2%7D-w%20%5Cend%7Bgathered%7D)
Step-by-step explanation:
To solve the following equations, we need to isolate the variable asked using inverse operations to solve equations.
Remember that addition and subtraction are inverse operations, as multiplication and division.
Therefore,
![\begin{gathered} a\text{. Solve for y} \\ 6y=9x-54 \\ y=\frac{9}{6}x-\frac{54}{6} \\ y=\frac{9}{6}x-9 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20a%5Ctext%7B.%20Solve%20for%20y%7D%20%5C%5C%206y%3D9x-54%20%5C%5C%20y%3D%5Cfrac%7B9%7D%7B6%7Dx-%5Cfrac%7B54%7D%7B6%7D%20%5C%5C%20y%3D%5Cfrac%7B9%7D%7B6%7Dx-9%20%5Cend%7Bgathered%7D)
F(x) = -64 I'm pretty sure.