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allsm [11]
3 years ago
11

If Agnes buys 6 apples, 5 bananas, and 2 oranges ,the cost will be $2.85. If she buys 3 apples, 7 bananas, and 4 oranges ,the co

st will be $2.70. If apples are 1 cent less than twice as expensive as oranges ,what is the cost of each?
Mathematics
1 answer:
Alona [7]3 years ago
7 0

im truly a dum person i am bad at my maths :\

Step-by-step explanation: 57/20 maybe if im wrong i already told you i am a dumb at my maths :P

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Shelley ran 20 minutes and burned 130 calories. How many calories did Shelly burn per minute?
Savatey [412]
ANSWER

6.5 calories per minute.

EXPLANATION

To find the calories Shelley burned per minute, divide the total calories burned by the total minutes ran.

Calories burned for a minute

= \frac{130}{20}

This will give us,

= \frac{13}{2}

= 6.5 \: calories
3 0
4 years ago
A rectangular prism has a base that is 5 cm by 7 cm and a height of 12 cm. if all dimensions are doubled, what happens to the vo
Maurinko [17]
We know, Volume of rectangular prism = l * b * h
If all dimensions are doubled, then it would be: 2 * 2 * 2 * v
V' = 8V

In Short, Volume will increase to it's 8 times

Hope this helps!
7 0
3 years ago
Read 2 more answers
Please help, i need it for a test, I'll give you brainliest :]
blagie [28]

Answer:

Step-by-step explanation:

C

4 0
3 years ago
The population of a certain town was 10,000 in 1990. The rate of change of the population, measured in people per year, is model
Katena32 [7]

The question is incomplete. The complete question is :

The population of a certain town was 10,000 in 1990. The rate of change of a population, measured in hundreds of people per year, is modeled by P prime of t equals two-hundred times e to the 0.02t power, where t is measured in years since 1990. Discuss the meaning of the integral from zero to twenty of P prime of t, d t. Calculate the change in population between 1995 and 2000. Do we have enough information to calculate the population in 2020? If so, what is the population in 2020?

Solution :

According to the question,

The rate of change of population is given as :

$\frac{dP(t)}{dt}=200e^{0.02t}$  in 1990.

Now integrating,

$\int_0^{20}\frac{dP(t)}{dt}dt=\int_0^{20}200e^{0.02t} \ dt$

                    $=\frac{200}{0.02}\left[e^{0.02(20)}-1\right]$

                   $=10,000[e^{0.4}-1]$

                    $=10,000[0.49]$

                    =4900

$\frac{dP(t)}{dt}=200e^{0.02t}$

$\int1.dP(t)=200e^{0.02t}dt$

$P=\frac{200}{0.02}e^{0.02t}$

$P=10,000e^{0.02t}$

$P=P_0e^{kt}$

This is initial population.

k is change in population.

So in 1995,

$P=P_0e^{kt}$

   $=10,000e^{0.02(5)}$

   $=11051$

In 2000,

$P=10,000e^{0.02(10)}$

   =12,214

Therefore, the change in the population between 1995 and 2000 = 1,163.

8 0
3 years ago
I need help with this
miv72 [106K]

Answer:

y = -x + 3

Step-by-step explanation:

8 0
3 years ago
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