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adoni [48]
2 years ago
14

The one above me is right

Mathematics
1 answer:
igomit [66]2 years ago
6 0
Huh? What’s above it?
You might be interested in
WHY IS THIS GETTING DELETED?? I NEED HELP
aliina [53]

If this exact question is repeatedly deleted, it's probably because of the ambiguity of the given equation. I see two likely interpretations, for instance:

\dfrac{(5\times5)^k}{5^{-8}} = 5^3

or

\dfrac{5\times 5^k}{5^{-8}} = 5^3

If the first one is what you intended, then

\dfrac{(5\times5)^k}{5^{-8}} = \dfrac{(5^2)^k}{5^{-8}} = \dfrac{5^{2k}}{5^{-8}} = 5^{2k-(-8)} = 5^{2k+8} = 5^3

and it follows that

2<em>k</em> + 8 = 3   ==>   2<em>k</em> = -5   ==>   <em>k</em> = -5/2

If you meant the second one, then

\dfrac{5\times 5^k}{5^{-8}} = \dfrac{5^1\times5^k}{5^{-8}} = \dfrac{5^{k+1}}{5^{-8}} = 5^{k+1-(-8)} = 5^{k+9} = 5^3

which would give

<em>k</em> + 9 = 3   ==>   <em>k</em> = -6

And for all I know, you might have meant some other alternative... When you can, you should include a picture of your problem.

3 0
3 years ago
How u do this question
creativ13 [48]
It wont let me see the pic sorry
try again
7 0
3 years ago
Round 150,893 to the nearest thousand.
Kaylis [27]

Answer:

151,000

Step-by-step explanation:

7 0
3 years ago
How to solve this? Please explain your answer! Thanks!
Murrr4er [49]

Answer:

The mean.

Step-by-step explanation:

I would use the mean as the measure of central tendency.

It is the best representation of the data as the variability isn't high; I'd only use the median if outliers are present because outliers don't affect it.

Because there are no outliers here, the mean is better.

Hopefully I helped :)

4 0
3 years ago
6.4 x 1.2 show your work
zimovet [89]

Answer:

7.68

Step-by-step explanation:

8 0
3 years ago
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