Answer: the observer should consider to eliminate or to retake the third measure.
Explanation:
The four measures taken are 124.53, 124.55, 142.51 and 124.52.
As it can be easily seen, the third measure is much different from the other three. This means that something went wrong during the observation: it can be either the measure taken wrong or that the number was written wrong (if you switch the 2 and the 4 you get a number similar to the other ones).
If the third measure is not considered, an estimate of the mean would place it around 124.5, while if the outlier (the detatched number) is considered an estimate of the mean would increase to about 129.
Therefore, in order to obtain a more reliable mean, the observer should consider to eliminate or to retake the third measure.
commercial time 6mins per 24 mins
in 1h 36 m (=96mins) there are 4 - 24 minute periods. Therefore there are 4 x6mins of commercial time = 24mins
Answer:
c) 18 cm²
d) 30 cm²
Step-by-step explanation:
c)
You can do this 2 different ways. Either way, you need to use the bottom side of 8 cm and the two congruent segments. Each of the two congruent segments of the bottom side measures 4 cm.
Method 1) Find the area of the large triangle and subtract from it the area of the small triangle.
area of triangle = bh/2
shaded area = 8 cm × 6 cm / 2 - 4 cm × 3 cm / 2
shaded area = 24 cm² - 6 cm²
shaded area = 18 cm²
Method 2) The shaded region is a trapezoid with parallel bases of lengths 3 cm and 6 cm and height 4 cm. Find the area of the trapezoid.
area of trapezoid = (B + b)h/2
shaded area = (6 cm + 3 cm)(4 cm)/2
shaded area = (9 cm)(4 cm)/2
shaded area = 18 cm²
d)
The area of the shaded region is the area of the white triangle subtracted from the area of the rectangle.
area of rectangle = length × width
area of triangle = bh/2
shaded area = (12 cm)(4 cm) - (9 cm)(4 cm)/2
shaded area = 48 cm² - 18 cm²
shaded area = 30 cm²
