Answer:
- 4 and 3
Step-by-step explanation:
Given
f(n) = 7n - 11
To evaluate f(1) and f(2) substitute n = 1 and n = 2 into f(n), that is
f(1) = 7(1) - 11 = 7 - 11 = - 4
f(2) = 7(2) - 11 = 14 - 11 = 3
Answer:
2
Step-by-step explanation:
The "average value of function f(x) on interval [a, b] is given by:
f(b) - f(a)
ave. value = ---------------
b - a
Here f(t)=(t-2)^2.
Thus, f(b) = (b - 2)^2. For b = 6, we get:
f(6) = 6^2 - 4(6) + 4, or f(6) = 36 - 24 + 4 = 16
For a = 0, we get:
f(0) = (0 - 2)^2 = 4
Plugging these results into the ave. value function shown above, we get:
16 - 4
ave. value = ------------ = 12/6 = 2
6 - 0
The average value of the function f(t)=(t-2)^2 on [0,6] is 2.
Answer:
c
Step-by-step explanation:
Answer:
x = 3
y = 8
Step-by-step explanation:
Since it gives you x, you need to plug in the number given for it into the equation:
y = 3x - 1
y = 3(3) - 1
y = 9 - 1
y = 8
So now you have, x = 3 and y = 8
