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guapka [62]
3 years ago
10

write the following inequality in slope-intercept form. –6x 2y ≤ 42 a. y ≥ 3x 21 b. y ≤ 3x – 21 c. y ≥ 3x – 21 d. y ≤ 3x 21

Mathematics
2 answers:
siniylev [52]3 years ago
6 0

For this case we have the following inequality:


-6x + 2y \leq 42

We want to rewrite the inequality in its slope-intercept form.


To do this, we must clear the value of y.


We have then:


2y \leq 6x + 42

Then, we have:


y \leq 3x + 21

Answer:


The inequality in slope-intercept form is given by:


y \leq 3x + 21


borishaifa [10]3 years ago
4 0
-6x + 2y =< 42
2y =< 6x + 42
y =< 3x + 21
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2 years ago
Arrange these functions from the greatest to the least value based on the average rate of change in the specified interval.
Romashka [77]
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 AVR =  \frac{f(x2)-f(x1)}{x2-x1}
 We will calculate AVR for each of the functions.
 We have then:

 f(x) = x^2 + 3x interval: [-2, 3]:
 f(-2) = x^2 + 3x  = (-2)^2 + 3(-2) = 4 - 6 = -2&#10;&#10;f(3) = x^2 + 3x = (3)^2 + 3(3) = 9 + 9 = 18
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 f(x) = 3x - 8 interval: [4, 5]:
 f(4) = 3(4) - 8 = 12 - 8 = 4 f(5) = 3(5) - 8 = 15 - 8 = 7
 AVR = \frac{7-4}{5-4}
 AVR = \frac{3}{1}
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 f(x) = x^2 - 2x interval: [-3, 4]
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 f(x) = x^2 - 5 interval: [-1, 1]
 f(-1) = (-1)^2 - 5 = 1 - 5 = -4&#10;&#10;f(1) = (1)^2 - 5 = 1 - 5 = -4
 AVR = \frac{-4+4}{1+1}
 AVR = \frac{0}{2}
 AVR = 0


 Answer:
 
these functions from the greatest to the least value based on the average rate of change are:
 f(x) = x^2 + 3x
 
f(x) = 3x - 8
 
f(x) = x^2 - 5
 
f(x) = x^2 - 2x
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