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2 years ago

Which of these has the largest value?A 1¹B 2¹C 2³D 3²

Mathematics

1 answer:

Anettt [7]2 years ago

6 0

D has the largest value

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Solve the equation for all real solutions in the simplest form. -5z^2-3z-11=-6z^2

horsena [70]

Answer:

-3z-11=11z^2

Step-by-step explanation:

3 0

2 years ago

Problem 4: Let F = (2z + 2)k be the flow field. Answer the following to verify the divergence theorem: a) Use definition to find

Viktor [21]

Given that you mention the divergence theorem, and that part (b) is asking you to find the downward flux through the disk $x^2+y^2\le3$ , I think it's same to assume that the hemisphere referred to in part (a) is the upper half of the sphere $x^2+y^2+z^2=3$ .

a. Let $C$ denote the hemispherical <u>c</u>ap $z=\sqrt{3-x^2-y^2}$ , parameterized by

$\vec r(u,v)=\sqrt3\cos u\sin v\,\vec\imath+\sqrt3\sin u\sin v\,\vec\jmath+\sqrt3\cos v\,\vec k$

with $0\le u\le2\pi$ and $0\le v\le\frac\pi2$ . Take the normal vector to $C$ to be

$\vec r_v\times\vec r_u=3\cos u\sin^2v\,\vec\imath+3\sin u\sin^2v\,\vec\jmath+3\sin v\cos v\,\vec k$

Then the upward flux of $\vec F=(2z+2)\,\vec k$ through $C$ is

$\displaystyle\iint_C\vec F\cdot\mathrm d\vec S=\int_0^{2\pi}\int_0^{\pi/2}((2\sqrt3\cos v+2)\,\vec k)\cdot(\vec r_v\times\vec r_u)\,\mathrm dv\,\mathrm du$

$\displaystyle=3\int_0^{2\pi}\int_0^{\pi/2}\sin2v(\sqrt3\cos v+1)\,\mathrm dv\,\mathrm du$

$=\boxed{2(3+2\sqrt3)\pi}$

b. Let $D$ be the disk that closes off the hemisphere $C$ , parameterized by

$\vec s(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath$

with $0\le u\le\sqrt3$ and $0\le v\le2\pi$ . Take the normal to $D$ to be

$\vec s_v\times\vec s_u=-u\,\vec k$

Then the downward flux of $\vec F$ through $D$ is

$\displaystyle\int_0^{2\pi}\int_0^{\sqrt3}(2\,\vec k)\cdot(\vec s_v\times\vec s_u)\,\mathrm du\,\mathrm dv=-2\int_0^{2\pi}\int_0^{\sqrt3}u\,\mathrm du\,\mathrm dv$

$=\boxed{-6\pi}$

c. The net flux is then $\boxed{4\sqrt3\pi}$ .

d. By the divergence theorem, the flux of $\vec F$ across the closed hemisphere $H$ with boundary $C\cup D$ is equal to the integral of $\mathrm{div}\vec F$ over its interior:

$\displaystyle\iint_{C\cup D}\vec F\cdot\mathrm d\vec S=\iiint_H\mathrm{div}\vec F\,\mathrm dV$

We have

$\mathrm{div}\vec F=\dfrac{\partial(2z+2)}{\partial z}=2$

so the volume integral is

$2\displaystyle\iiint_H\mathrm dV$

which is 2 times the volume of the hemisphere $H$ , so that the net flux is $\boxed{4\sqrt3\pi}$ . Just to confirm, we could compute the integral in spherical coordinates:

$\displaystyle2\int_0^{\pi/2}\int_0^{2\pi}\int_0^{\sqrt3}\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=4\sqrt3\pi$

4 0

3 years ago

The Tour de France is a bike race around the country of France. The bike race is a three week race that covers approximately 2,2

valentinak56 [21]

Answer:

Approximately 54.54% of race happened in the first week.

Step-by-step explanation:

We are given the following in the question:

Length of bike race in three weeks = 2,200 miles

Race covered in first week = 1,200 miles

Percentage of race covered in first week =

$=\dfrac{\text{Race covered in first week}}{\text{Total length of race}}\times 100\%\\\\=\dfrac{1200}{2200}\times 100\%\\\\=54.54\%$

Thus, approximately 54.54% of race happened in the first week.

4 0

2 years ago

Products equivalent to the quotient of 9/ divided by 2

Murljashka [212]

Answer:

$\frac{3}{\sqrt{2} }^2$

Step-by-step explanation:

8 0

3 years ago

Explain how you would solve 25- 6R when R = 3. Make sure to explain each step.

aliina [53]

Fist you need to substitute the value of R into the equation

25-6(3)

Now you simply
First multiple 6(3)

25-6(3)
25-18

Now solve!
25-18
7

The answer is 7

4 0

3 years ago

Which of these has the largest value?A 1¹B 2¹C 2³D 3²​

Which of these has the largest value?A 1¹B 2¹C 2³D 3²