Answer:
Both A and C is the right
Maybe because of global warming and the glacier water melting makING it bigger and deeper. (I hope this is the answer you are looking for)
<span>In Drosophila + indicates wild-type allele for any gene, m is mahogany and e is ebony.
Female parents are m+/m+ and males are +e/+e.
F1 are m+/+e, all wild type. F1 females are crossed with me/me males - the test cross.
Offspring will be : non recombinant m+/me, mahogany wild type or +e/me wild type ebony. OR
recombinant me/me mahogany ebony or ++/++ wild type.
As the two genes are 25 map units apart, the percentage of recombinants will be 25% and therefore percentage parental types will be 75%.
75% 1000 is 750. There are two parental types, so you would expect 375 of each. Therefore, you would expect 375 m+/me and 375 +e/me.
25% of 1000 is 250 split between two recombinants =125 of each. Therefore you would expect 135 me/me and 125 ++/++</span>
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Assuming she reproduces with someone who doesn't have the color blind gene:
XcXc * XCY
There are 4 combinations
XcXC
XcXC
XcY
XcY
As both of the males have the Xc gene, she can expect 100% of her male offspring to be colorblind.
