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2 years ago

14

5x + 10y +30z

1 answer:

ratelena [41]2 years ago

3 0

Answer:

The answer is 5x + 10y + 30z.

the can't be combined because they all have different variables.

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Factor the Expression and choose the correct answer from the choices below.

pentagon [3]

The answer is (5p+6q)(5p-6q)
Steps:
Apply difference of the squares rule: x^2-y^2=(x+y)(x-y)
25p^2-36q^2=(5p+6q)(5p-6q)

Hope this helps you! (:
-PsychoChicken4040

3 0

2 years ago

What is k+3 3/4 = 5 2/3 - 1 1/3

zhenek [66]

K+3 3/4=5 2/3-1 1/3
k+3 3/4=4 1/3
lets find the lcm first then multiply both sides by it but first change it to improper fraction
LCM is 12

[k+15/4]=[13/3]12
12k+45=52
12k=7
k=7/12

4 0

2 years ago

From a practice assignment:<br>solve the following differential equation given initial conditions

hodyreva [135]

If $y' = e^y \sin(x)$ and $y(-\pi)=0$ , separate variables in the differential equation to get

$e^{-y} \, dy = \sin(x) \, dx$

Integrate both sides:

$\displaystyle \int e^{-y} \, dy = \int \sin(x) \, dx \implies -e^{-y} = -\cos(x) + C$

Use the initial condition to solve for $C$ :

$-e^{-0} = -\cos(-\pi) + C \implies -1 = 1 + C \implies C = -2$

Then the particular solution to the initial value problem is

$-e^{-y} = -\cos(x) - 2 \implies e^{-y} = \cos(x) + 2$

(A)

4 0

1 year ago

Y=1/4x+5<br> y=-x<br>what are the x and y values, I think I'm supposed to use substitute

I am Lyosha [343]

Answer:

the answer are x=4y-20

and x represents the independent variable and y represents the dependent variable

5 0

2 years ago

Find the standard form of the circle x2 + y2 – 6x + 10y + 24 = 0 by completing the square.

hichkok12 [17]

Answer:

$(x-3)^2+ (y+5)^2=10$

Step-by-step explanation:

Given the equation of the circle: $x^2 + y^2 - 6x + 10y + 24 = 0$

We wish to express it in a Standard form:

We begin by re-arranging:

$x^2 - 6x + y^2 + 10y = - 24$

Next, divide the coefficient of x by 2, square it and add it to both sides.

Do the same for y.

$x^2 - 6x +(-3)^2+ y^2 + 10y+5^2 = - 24+(-3)^2+5^2$

Next, we factorize

$(x-3)^2+ (y+5)^2 = - 24+9+25\\(x-3)^2+ (y+5)^2=10$

This is the standard form.

6 0

2 years ago