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Aneli [31]
3 years ago
14

Different varieties of field daisies have numbers of petals that follow a fibonacci sequence.Three varieties have 13,21, and 347

petals.
How many petals do the next two varieties of field daisy have?

a. 42, 55
b. 47,60
c. 42,50
d. 55,89
Mathematics
1 answer:
EleoNora [17]3 years ago
7 0
The answer is letter d. The Fibonacci Sequence states to add the 2 previous number to get the next number starting with 1. So, 1 + 0=1, 1+1=2, 1+2=3, 2+3=5,3+5=8, 5+8=13, etc....

I added 13+21 to get 34. Then add 21+34 to get 55. Then add 34+55 to get 89.
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Step-by-step explanation:

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Answer:

a) \bar X = 369.62

b) Median=175

c) Mode =450

With a frequency of 4

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Step-by-step explanation:

We have the following data set given:

49 70 70 70 75 75 85 95 100 125 150 150 175 184 225 225 275 350 400 450 450 450 450 1500 3000

Part a

The mean can be calculated with this formula:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

Replacing we got:

\bar X = 369.62

Part b

Since the sample size is n =25 we can calculate the median from the dataset ordered on increasing way. And for this case the median would be the value in the 13th position and we got:

Median=175

Part c

The mode is the most repeated value in the sample and for this case is:

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Part d

The midrange for this case is defined as:

MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5

Part e

For this case we can calculate the deviation given by:

s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And replacing we got:

s = 621.76

And we can find the limits without any outliers using two deviations from the mean and we got:

\bar X+2\sigma = 369.62 +2*621.76 = 1361

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

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