Answer: 12 ( answer not among the option)
Explanation:
From the equation of reaction; P4O10+ H2O -----> H3PO4, it is unbalanced.
One can only get the exact number of ''Hydrogen atom'' if it is well balanced.
Adding '4' to H3PO4 on the RHS and '6' to H2O on LHS of the equation would give a balanced equation such as;
P4O10 + 6H2O -----> 4 H3PO4
Therefore the number of hydrogen atoms found on the reactant is 12.
First, we determine the moles of Mg(NO₃)₂ present:
moles = mass / Mr
= 46.5 / (24 + 2 x (14 + 16 x 3))
= 0.4 mole
Each mole of Mg(NO₃)₂ contains 2 moles of Nitrogen atoms.
Moles Nitrogen = 0.4 x 2
= 0.8 mole
Answer:
pH of Buffer Solution 5.69
Explanation:
Mole of anhydrous sodium acetate = 
= 
= 0.18 mole
100 ml of 0.2 molar acetic acid means
= M x V
= 0.2 x 100
= 20 mmol
= 0.02 mole
Using Henderson equation to find pH of Buffer solution
pH = pKa + log![\frac{[Salt]}{[Acid]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BSalt%5D%7D%7B%5BAcid%5D%7D)
= 4.74 + log
= 4.74 + log 9
= 5.69
So pH of the Buffer solution = 5.69
The concentration of each of the individual ions in a 0750 M Ba(OH)2 solution is
[Ba2+] = 0.750 M
[OH-]= 1.50 M
<h3>
calculation</h3>
write the equation for dissociation
that is Ba(OH)2 (s)→ Ba2+(aq) + 2OH-(aq)
by use of mole ratio of Ba(OH)2 : Ba2+ which is 1: 1 the concentration of Ba2+ is therefore= 0.750M
by use of mole ratio of Ba(OH)2 : OH- which is 1:2 the concentration of OH- =0.750 M x2/1=1.50 M
