Answer:
chlorous acid HClO₂
Explanation:
The Ka is the acidity constant and it tells you about the acidity strength of a compound. If the value of Ka is high the compound is a strong acid. If the value of Ka is low the compound is a weak acid.
The problem gives us the following compounds with the Ka values:
HF, 3.5 × 10⁻⁴
HCOOH, 1.8 × 10⁻⁴
HClO₂, 1.1 × 10⁻²
HCN, 4.9 × 10⁻¹⁰
HNO₂, 4.6 × 10⁻4
The chlorous acid HClO₂ have the highest Ka, 1.1 × 10⁻², so this one is the strongest acid.
Answer:
Explanation:
Hello!
In this case, for this problem, it is possible to use the thermodynamic definition of the Gibbs free energy:
Whereas G, H and S can be assumed as constant over T; thus, we can calculate H at 135.4 °C:
Now, we can calculate the Gibbs free energy at 12.7 °C as shown below:
Best regards!
Answer:
lost 2 electrons
Explanation:
A <em>cation</em> by definition is a positively charged ion. They are formed when a metal loses its electrons. A cation has more protons than electrons, giving it a net positive charge. So, it had to have lost 2 electrons to give it a positive charge of 2⁺.
This is the answer for the question above:
In order to solve this, first use stoichiometry for the energy in kJ released by, converting grams of CuO2 to moles:
<span>56.96g*(1 mole/143.09 g)=0.41904 moles of Cu2O </span>
<span>2 moles of Cu2O=-292.0kJ Convert 0.41904 moles of Cu2O to kJ. </span>
<span>Finally, solve for kJ: </span>
<span>0.41904 moles of Cu2O*(-292.0kJ/2 moles of Cu2O)=-61.18 kJ of energy released</span>
Answer:
A) Carbon
Explanation:
the others are wrong its A