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lbvjy [14]
3 years ago
15

HELP

Chemistry
1 answer:
agasfer [191]3 years ago
5 0

Answer:

3.02× 10²⁴ atoms

Explanation:

Given data:

Number of nitrogen atoms = ?

Number of moles of N₂O = 2.51 mol

Solution:

1 mole contain 2 mole of nitrogen atoms.

2.51 × 2 = 5.02  mol

According to Avogadro number,

1 mole = 6.022 × 10²³ atoms

5.02  mol ×  6.022 × 10²³ atoms / 1 mol

30.2 × 10²³ atoms

3.02× 10²⁴ atoms

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Will mark the brainiest later for correct answers! Please show work.
Elodia [21]

Answer:

According to avogadro's law, 1 mole of every substance contains avogadro's number 6.023\times 10^{23} of particles and weighs equal to its molecular mass.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

\text{Number of moles}=\frac{\text{Given molecules}}{\text {Avogadros number}}

a. moles in 14.08 g of C_{12}H_{22}O_{11} = \frac{14.08g}{342.3g/mol}=0.04113moles

molecules in 14.08 g of C_{12}H_{22}O_{11} = 0.04113\times 6.023\times 10^{23}=0.2477\times 10^{23}

b. moles in 17.75 g of NaCl = \frac{17.75g}{58.5g/mol}=0.3034moles

molecules in 17.75 g of NaCl = 0.3034\times 6.023\times 10^{23}=1.827\times 10^{23}

formula units 17.75 g of NaCl = 0.3034\times 6.023\times 10^{23}=1.827\times 10^{23}

c. moles in 20.06 g of  CuSO_4.5H_2O= \frac{20.06g}{249.68g/mol}=0.08034moles

formula units in 20.06 g of  CuSO_4.5H_2O= 0.08034\times 6.023\times 10^{23}=0.4839\times 10^{23}

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3 years ago
Do humans really have a third eye
Dominik [7]
Well I wouldn't quite call it a third eye but yes we have the ability to see things if we connect to our inner selves
6 0
3 years ago
Read 2 more answers
F
Katarina [22]

The statement is true in this situation is C. The size of Ffric is the same as the size of Fapp:

From the diagram, since the body is in equilibrium, the sum of vertical forces equals zero. Also, the sum of horizontal forces equal zero.

So, ∑Fx = 0 and ∑Fy = 0

Since Fapp acts in the negative x - direction and Ffric acts in the positive x - direction,

∑Fx = -Fapp + Ffric = 0

-Fapp + Ffric = 0

Fapp = Ffric

Also, since Fgrav acts in the negative y - direction and Fnorm acts in the positive y - direction,

∑Fy = Fnorm + (-Fgrav) = 0

Fnorm - Fgrav = 0

Fnorm = Fgrav

So, we see that the size of Fapp <u>equals</u> size of Ffric and the size of Fnorm <u>equals</u> the size of Fgrav.

So, the correct option is C

The statement which is true in this situation is C. The size of Ffric is the same as the size of Fapp.

Learn more about equilibrium of forces here:

brainly.com/question/12980489

5 0
2 years ago
the volume of gas in a container was originally 3.24L, while at standard pressure 1.00 atm. what will the volume be if the press
Simora [160]
Hello!

To solve this problem, we will use the Boyle's Law, which describes how pressure changes when volume changes and vice-versa. The equation for this law is the following one, and we'll clear for V2:

P1*V1=P2*V2 \\ \\ V2= \frac{P1*V1}{P2}= \frac{3,24 L * 1 atm}{1,20 atm}= 2,7 L

So, the final volume after increasing the pressure would be 2,7 L. That means that volume decreases when the pressure increases

Have a nice day!
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Do centromeres divide at anaphase i or ii
ddd [48]
Anaphase 1 is when centromeres divide
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