Answer:
5 and 10 ... and ... 6 and 10
Step-by-step explanation:
I would say that this woud be your answer mainly because that that 10 by 5 is even. Which 5 by 2 would equal 10. Which would be equaled. Therefore, B would be your answer.
As we do see the other answers, 5 does not go into 12, and 6 does not go into 10. But our other answer would also look be 6 and 12.
You answer: B and D
Answer:
x=8 y=1
Step-by-step explanation:
you have first and second equation, YOU MUST FIND THE THIRD EQUATION
<em><u>SOLUTION</u></em><em><u> </u></em>
<em><u> </u></em><em><u>FIND</u></em><em><u> </u></em><em><u>equation</u></em><em><u> </u></em><em><u>3</u></em><em><u> </u></em><em><u>from</u></em><em><u> </u></em><em><u>2</u></em>
<em><u>x</u></em><em><u>+</u></em><em><u>2y</u></em><em><u>=</u></em><em><u>10</u></em>
<em><u>x</u></em><em><u>=</u></em><em><u>10-2y</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>3</u></em>
<em><u> </u></em><em><u>Substitute</u></em><em><u> </u></em><em><u>equation</u></em><em><u> </u></em><em><u>3</u></em><em><u> </u></em><em><u>from</u></em><em><u> </u></em><em><u>first</u></em><em><u> </u></em><em><u> </u></em><em><u>(</u></em><em><u>not</u></em><em><u> </u></em><em><u>from</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>equation</u></em><em><u> </u></em><em><u>where</u></em><em><u> </u></em><em><u>you</u></em><em><u> </u></em><em><u>got</u></em><em><u> </u></em><em><u>equation</u></em><em><u> </u></em><em><u>3</u></em><em><u>)</u></em>
2 (10-2y)-7y=9
20-4y-7y=9
-11y=9-20
-11y= -11
-11y/-11= -11/-11
y=1
<em><u>Find</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>value</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>x</u></em><em><u> </u></em><em><u>from</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>third</u></em><em><u> </u></em><em><u>equation</u></em><em><u> </u></em>
<em><u>x</u></em><em><u>=</u></em><em><u>10</u></em><em><u>-</u></em><em><u>2</u></em><em><u> </u></em><em><u>(</u></em><em><u>1</u></em><em><u>)</u></em>
<em><u>x</u></em><em><u>=</u></em><em><u>8</u></em>
Andrew invests $7600 in two different accounts. The first account paid 9 %, the second account paid 14% in interest. At the end of the first year he had earned $829 in interest. How much was in each account?
Let
x ------> the amount invested in account that paid 9 %
7,600-x ------> the amount invested in account that paid 14%
we have that
9%=9/100=0.09
14%=14/100=0.14
so
(x)*(0.09)+(7,600-x)*(0.14)=829
solve for x
0.09x-0.14x+1,064=829
0.14x-0.09x=1,064-829
0.05x=235
x=4,700
Find the value of (7,600-x)
7,600-4,700=2,900
therefore
the answer is
<h2> the amount invested in account that paid 9 % was $4,700</h2><h2>the amount invested in account that paid 14% was $2,900</h2>
C=2πr
C=πd
A=πr^2
r=C/2π
r=1/2 d
<u>By the way all you do to solve r is: </u>
C=2πr
C/2π=2πr/2π
C/2π=r
r=C/2π
Hope this helps:)