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garik1379 [7]
3 years ago
13

Please help it’s URGENT

Mathematics
2 answers:
Radda [10]3 years ago
8 0
I think it’s k and i am sorry if i am wrong but yeah…
kozerog [31]3 years ago
5 0
The answer is K. The reasoning is because there is a decrease of -4 every y for every x making it linear because it’s a subtraction or addition trend
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Which function has an inverse that is also a function? {(–1, –2), (0, 4), (1, 3), (5, 14), (7, 4)} {(–1, 2), (0, 4), (1, 5), (5,
Mkey [24]

Answer:

C. {(–1, 3), (0, 4), (1, 14), (5, 6), (7, 2)}

Step-by-step explanation:

I just did the quiz. Basically all you do is switch the x and y values for each coordinate pair in order to see if it would pass the line test. If it has double X values, it is not a function with an inverse function.

5 0
4 years ago
Can someone please help me!
victus00 [196]

Answer:

33°

Step-by-step explanation:

11x = 1/2(x+63)

22x = x + 63

21x = 63

x = 3

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= 11(3) = 33°

8 0
4 years ago
The base of the triangle is 5<img src="https://tex.z-dn.net/?f=%5Csqrt%7B3%7D" id="TexFormula1" title="\sqrt{3}" alt="\sqrt{3}"
Vsevolod [243]

Answer:

yes you are absolutely right

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4 0
3 years ago
A random sample of 28 statistics tutorials was selected from the past 5 years and the percentage of students absent from each on
SVEN [57.7K]

Answer:

Step-by-step explanation:

Hello!

X: number of absences per tutorial per student over the past 5 years(percentage)

X≈N(μ;σ²)

You have to construct a 90% to estimate the population mean of the percentage of absences per tutorial of the students over the past 5 years.

The formula for the CI is:

X[bar] ± Z_{1-\alpha /2} * \frac{S}{\sqrt{n} }

⇒ The population standard deviation is unknown and since the distribution is approximate, I'll use the estimation of the standard deviation in place of the population parameter.

Number of Absences 13.9 16.4 12.3 13.2 8.4 4.4 10.3 8.8 4.8 10.9 15.9 9.7 4.5 11.5 5.7 10.8 9.7 8.2 10.3 12.2 10.6 16.2 15.2 1.7 11.7 11.9 10.0 12.4

X[bar]= 10.41

S= 3.71

Z_{1-\alpha /2}= Z_{0.95}= 1.645

[10.41±1.645*(\frac{3.71}{\sqrt{28} } )]

[9.26; 11.56]

Using a confidence level of 90% you'd expect that the interval [9.26; 11.56]% contains the value of the population mean of the percentage of absences per tutorial of the students over the past 5 years.

I hope this helps!

7 0
4 years ago
Which expression is always equivalent to sin X when 0 &lt; x &lt;90
MA_775_DIABLO [31]
 cos (90° - x) should be the answer 
7 0
3 years ago
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