Answer:
P(3) is true since 2(3) - 1 = 5 < 3! = 6.
Step-by-step explanation:
Let P(n) be the proposition that 2n-1 ≤ n!. for n ≥ 3
Basis: P(3) is true since 2(3) - 1 = 5 < 3! = 6.
Inductive Step: Assume P(k) holds, i.e., 2k - 1 ≤ k! for an arbitrary integer k ≥ 3. To show that P(k + 1) holds:
2(k+1) - 1 = 2k + 2 - 1
≤ 2 + k! (by the inductive hypothesis)
= (k + 1)! Therefore,2n-1 ≤ n! holds, for every integer n ≥ 3.
Hey there :)
Writing in scientific notation means a should be
0 ≤ a < 10
Therefore, 0.000309 will be written as
3.09 x 10ⁿ
3 is the 4th decimal place value
so n = - 4
3.04 x 10⁻⁴
Yes my mom and mom I got a baby text you baby text me when your baby girl love mom
Given:
The ratio of red and blue cubes is 4:7.
After adding 10 more red cubes the ratio of red and blue cubes is 6:7.
To find:
The number of blue cubes.
Solution:
The ratio of red and blue cubes is 4:7.
Let the number of red and blue cubes be 4x and 7x respectively.
After adding 10 more red cubes.
Number of red cubes = 4x+10
Then, the ratio of red and blue cubes is 6:7.





Divide both sides by 14.

Now,
Number of blue cubes in the bag is

Therefore, the number of blue cubes is 35.
<span>C/9 - 8 = 17
------------
Simplify
1/9c - 8 = 17
----------------
Add 8 to each side
1/9c - 8 + 8</span><span> </span><span>= 17 + 8
1/9c = 25
--------------------
Multiply each side by 9
9 * 1/9c = 9 * 25
c = 225</span>