What is the equation of the line that is perpendicular to y = one-fifth x + 4 and that passes through (5,–4)?
2 answers:
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<u>Answer:</u>
D) 6x^2 - 8y^2 = 50
-6x^2 - 2y^2 = 11
<u>Step-by-step explanation:</u>
We are given the following two expressions:
and
Now if we look at the option D) and
, we can observe that the earlier part in the given expression is just a simplification of 6x^2 - 8y^2 = 50.
and the later part is already the same.
Therefore, the correct answer option is D) 6x^2 - 8y^2 = 50
-6x^2 - 2y^2 = 11.
