3 years ago

What is the equation of the line that is perpendicular to y = one-fifth x + 4 and that passes through (5,–4)?

Mathematics

2 answers:

Brilliant_brown [7]3 years ago

8 0

Answer:

y = -5x + 21

Step-by-step explanation:

perpendicular lines have slopes that are negative reciprocals.

The given line has a slope of 1/5, so the perpendicular line will have a slope of -5.

y = -5x + B

-4 = -5(5) + B

B = -4 + 25 = 21

y = -5x + 21

Thepotemich [5.8K]3 years ago

8 0

Answer:

Step-by-step explanation:

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