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Goshia [24]
3 years ago
5

Apply the distributive property to convert the expression to the greatest common factor multiplied by a term in parenthesis.

Mathematics
1 answer:
puteri [66]3 years ago
3 0

Answer:

9(4a+1)=

10(4+5d)=

7(4-f)=

Step-By-Step Solution:

The greatest common factor is the largest number that both numbers can be divided by. For example, in #1, 36 and 9 can both be divided by 9 to become 4 and 1.

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Drag each tile to the correct box.
mr_godi [17]

Answer:

-2.76

-2.57

-2.5

-1.85

-1.58

2.5

2.85

Hopefully this is what you mean. Have a nice day!

Step-by-step explanation:

7 0
3 years ago
PLEASE PEOPLE , I NEED HELP CAN YOU HELP ME PLEASE :,)
Tasya [4]

Step-by-step explanation:

= (1 + 5z)(-4)

= (1 + 5z) × (-4)

= 1.(-4) + 5z. (-4)

= -4 - 20z

3 0
2 years ago
Helppppppppppppppppppppppppppppppppp
liq [111]

Answer:

The answer is B

you should still invest in a calculator (:

4 0
2 years ago
What is the solution to the system of equations shown below?
Alexxandr [17]

Answer:

  b.  (1, 3, ­-2)

Step-by-step explanation:

A graphing calculator or scientific calculator can solve this system of equations for you, or you can use any of the usual methods: elimination, substitution, matrix methods, Cramer's rule.

It can also work well to try the offered choices in the given equations. Sometimes, it can work best to choose an equation other than the first one for this. The last equation here seems a good one for eliminating bad answers:

  a: -1 -5(1) +2(-4) = -14 ≠ -18

  b: 1 -5(3) +2(-2) = -18 . . . . potential choice

  c: 3 -5(8) +2(1) = -35 ≠ -18

  d: 2 -5(-3) +2(0) = 17 ≠ -18

This shows choice B as the only viable option. Further checking can be done to make sure that solution works in the other equations:

  2(1) +(3) -3(-2) = 11 . . . . choice B works in equation 1

  -(1) +2(3) +4(-2) = -3 . . . choice B works in equation 2

7 0
3 years ago
PLEASE HELP ME ASAP
velikii [3]

Answer:

Radius r=0.30m, Velocity, v=36m/s

(a) angular speed w=

r

v

=

0.3

36

=120rad/s

(b) final angular speed w

′

=0

From rotational kinematics w

′

2

−w

2

=2αθ

0−14400=2α×40×2π

⇒α=

160π

−14400

=−28.6rad/s

2

'Distance covered

=40×2πr

=40×2π×0.3=75.39m

5 0
2 years ago
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