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Goshia [24]
2 years ago
5

Apply the distributive property to convert the expression to the greatest common factor multiplied by a term in parenthesis.

Mathematics
1 answer:
puteri [66]2 years ago
3 0

Answer:

9(4a+1)=

10(4+5d)=

7(4-f)=

Step-By-Step Solution:

The greatest common factor is the largest number that both numbers can be divided by. For example, in #1, 36 and 9 can both be divided by 9 to become 4 and 1.

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Venn Diagrams contain how many sets, depicted by circles?
Nadusha1986 [10]

Answer:

4

Step-by-step explanation:

8 0
3 years ago
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Nine and one-half less than four and one-half times a number is greater than 62.5. Which of the following represents the solutio
kolbaska11 [484]
4.5x - 9.5 > 62.5
4.5x > 62.5 + 9.5
4.5x > 72
x > 72/4.5
x > 16 <==
4 0
3 years ago
Read 2 more answers
45 children attend preschool the number of two-year-olds is 1/2 the number of three-year-olds the number for your old is the sam
Mkey [24]
There are 9 two-year-olds and 18 each of 3 and 4 year olds.

To solve this we could write and solve the equation below, letting x be the number of 3 and 4 year olds.

x/2 + x + x = 45
x + 2x + 2x = 90
5x = 90
x = 18

From here, we just divide 18 by 2 to get the number of 2 year olds.
6 0
3 years ago
Find the 14th term of the arithmetic sequence - 4x - 1, - 9x - 6 , -14x-11
Yanka [14]

Answer:

-69x-66

Step-by-step explanation:

1) given: a₁=-4x-1; a₂=-9x-6; a₃=-14x-11. Find: a₁₄-?

2) a₁₄=a₁+13d, where d - the difference between neighbor-terms;

3) d=a₂-a₁; ⇔ d= -9x-6+4x+1= -5x-5;

4) a₁₄= -4x-1+13*(-5x-5)= -69x-66.

3 0
2 years ago
The width of a rectangle field is 3h yards and its length is 3 yards longer than the width. The field has a fence around its per
d1i1m1o1n [39]

Answer:

Part a) P=(12h+2)\ yd

Part b) The expression that represent the cost of fencing the field is (336h+56)

Part c) \$1,736

Step-by-step explanation:

<u>The complete question in the attached figure</u>

Part a) we know that

The perimeter of the rectangular field (excluding the width of the gate) is equal to

P=2(L+W)-4

we have

L=(3h+3)\ yd\\W=3h\ yd

substitute the given values

P=2(3h+3+3h)-4

P=2(6h+3)-4\\P=12h+6-4\\P=(12h+2)\ yd

Part b) we know that

To find out the cost of fencing the field (excluding the gate) , multiply the perimeter by the cost of $28 per yard

so

28(12h+2)=336h+56

Part c) we have

h=5

substitute the value of h in the expression of the cost

336(5)+56=\$1,736

8 0
3 years ago
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