The polynomial cannot be factored in because it exists prime. Since 112 exists not a perfect square number so we cannot estimate the factors of the given equation.
<h3>What is a quadratic equation?</h3>
In a quadratic equation ax² + bx + c = 0
when (b² - 4ac) exists a perfect square only then we can factorize the equation.
In the given equation x² - 8x - 12 we have to determine the value of
b² - 4ac
From the equation, we get b = -8 and c = -12
b²- 4ac = (-8)² - 4(1)(-12)
= 64 + 48 = 112
Since 112 exists not a perfect square number so we can not estimate the factors of the given equation.
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The sign of f on the interval -7/3 < x < -3/5 is always positive.
<h3>How to solve for the sign on the interval</h3>
We have the equation
(5x+3)(x−2)(3x+7)(x+5) > 0
Now when f(x) > 0
Then -7/3 < x < -3/5
This would tell us that the sign would become positive when it changes from the less than to greater than sign
<h3>Complete Question</h3>
f(x)=(5x+3)(x-2)(3x+7)(x+5) has zeros at x=-5, x=-7/3, x=-3/5, and x=2
What is the sign of f on the interval -7/3<x<-3/5?
answer choices
f is always positive on the interval
f is always negative on the interval
f is sometimes positive and sometimes negative on the interval
f is never positive or negative on the interval
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169.65mm
A=2πrh+2πr2=2·π·3·6+2·π·32≈169.646
9.28 days are taken to completely fill the pool
It is given that one pipe can fill the pool in 10 days
the other pipe can fill it in 25 days.
if no sewage is added, waste removal will empty the pool in 31 days.
The amount filled by pipe one in 1 day=1/10
The amount of pool filled by second pipe in 1 day=1/25
The waste removal pipe's work in 1 day= 1/31
Therefore, the work done together by all pipes in one day=1/10+1/25-1/31
= (775+310-250)/31*25*10=835/7750
Therefore, number of days taken to empty the pool= 7750/835=9.28 days
As half day cannot be counted, hence 9.28 days are taken to completely fill the pool
Disclaimer: The waste removal pipe has also been taken into consideration
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