We now have three equations, so we can solve them.
Let's define the length of the 3 boards in terms of x:
F=x
S=2x-3
T=2
F+S+T =26
x+2x-3+2 =26
3x =26+1=27
x =27/3 = 9 feet for First section
2x-3 =18-3 = 16 feet = Second
2 = Third
9+16+2 = 27
27 is the length of the shortest piece.
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Answer:
about 65 percentage is the correct answer
Answer:
it would be a
Step-by-step explanation:
If a2 -2ab + b2 = 9 and a![\begin{gathered} a^2-2ab+b^2=9 \\ aStep 1 factorize[tex]\begin{gathered} a^2-2ab+b^2=(a-b)^2 \\ \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20a%5E2-2ab%2Bb%5E2%3D9%20%5C%5C%20a%3C%2Fp%3E%3Cp%3E%EF%BB%BFStep%201%20%3C%2Fp%3E%3Cp%3Efactorize%3C%2Fp%3E%5Btex%5D%5Cbegin%7Bgathered%7D%20a%5E2-2ab%2Bb%5E2%3D%28a-b%29%5E2%20%5C%5C%20%20%5Cend%7Bgathered%7D)
then
[tex]\begin{gathered} (a-b)^2=9 \\ \sqrt{(a-b)^2}=\sqrt{9} \\ a-b=\pm3 \\ \\ aa-b=-3
Answer:
3
Step-by-step explanation:
If you divide both numbers by x then it's just 1 and 3. LCM of 1 and 3 is 3
