sum of all sides of triangle=180°
7x+13x+16x=180°
36x=180°
x=180°/36
x=5
angle D=7x
=7(5)
D=35°
angle E=13(x)
=13(5)
E=65°
angle F=16x
=16(5)
F=80°
angle D=35°
angle E=65°
angle F=80°
If you mean in Roman numerals,it would be ___.VII. or it could be ((DCC))
Answer:
the solution is A
Step-by-step explanation:
![\sqrt[3]{27a^{3}b^{7} } \\](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27a%5E%7B3%7Db%5E%7B7%7D%20%20%7D%20%5C%5C)
![\sqrt[3]{(3)^3(a^3)(b^6)b}\\\\3ab^2\sqrt[3]{b}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%283%29%5E3%28a%5E3%29%28b%5E6%29b%7D%5C%5C%5C%5C3ab%5E2%5Csqrt%5B3%5D%7Bb%7D)