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Lapatulllka [165]
3 years ago
8

From long experience, it is known that the time it takes to do an oil change and lubrication job on a vehicle has a normal distr

ibution with a mean of 17.8 minutes and a standard deviation of 5.2 minutes. An auto service shop will give a free lube and oil change service to any customer who must wait beyond the guaranteed time to complete the work. If the shop does not want to give more than 1% of its customers a free lube and oil change service, how long should the guarantee be
Mathematics
1 answer:
djyliett [7]3 years ago
8 0

Answer: 29.916 minutes

Step-by-step explanation:

Given the following :

Mean of distribution = 17.8 minutes

Standard deviation of distribution = 5.2 minutes

Percentage of customers to give free lube and oil change service should not exceed 1% if the customer waits beyond the guaranteed time ;

Length of guarantee :

Since % of customers should not exceed 1%

Then probability of not being chosen = (1 - 0.01) = 0.99

Using the z table to find the Zscore of 0.99,

Zscore of 0.99 = 2.33

This is 2.33 standard deviations above the mean

(2.33 × standard deviation) + mean value

(2.33 × 5.2 minutes) + 17.8 minutes

12.116 + 17.8

= 29.916 minutes

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Answer:

Area covered by the fences will be 16.1 unit²

Step-by-step explanation:

Let the first parabola is represented by the function f(x) = 6x²

and second parabola by g(x) = x² + 9

point of intersection of the graphs will be determined when f(x) = g(x)

6x² = x² + 9

5x² = 9

x² = 1.8

x = ± 1.34

Now we will find the area between these curves drawn on the graph.

Area = \int_{-1.34}^{1.34}[f(x)-g(x)]dx=\int_{-1.34}^{1.34}[6x^{2}-(x^{2}+9)]dx

= \int_{-1.34}^{1.34}(5x^{2}-9)dx

= [\frac{5}{3}x^{3}-9x]_{-1.34}^{1.34}

= [\frac{5}{3}(-1.34)^{3}-9(-1.34)-\frac{5}{3}(1.34)^{3}+9(1.34)]

= [-4.01+12.06-4.01+12.06]

= 16.1 unit²

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3 years ago
How can I find the prime factorization of a number with an easy explanation?
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Step-by-step explanation:

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Step-by-step explanation:

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Check the picture below.

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