<em>Note: Your exponential expression seems a little unclear. Because 27 is not an exponential expression.</em>
<em>But, I am assuming that your exponential expression is:
</em>
<em>The reason is that my solution would still clear your concept about this topic, no matter what the question is.
</em>
<em>
</em>
Answer:
The simplified value of the exponential expression is:
![27^{\frac{1}{3}}=3](https://tex.z-dn.net/?f=27%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%3D3)
Step-by-step explanation:
Assuming the exponential expression
![\:27^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5C%3A27%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
![\mathrm{Factor\:the\:number:\:}\:27=3^3](https://tex.z-dn.net/?f=%5Cmathrm%7BFactor%5C%3Athe%5C%3Anumber%3A%5C%3A%7D%5C%3A27%3D3%5E3)
![=\left(3^3\right)^{\frac{1}{3}}](https://tex.z-dn.net/?f=%3D%5Cleft%283%5E3%5Cright%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
![\mathrm{Apply\:exponent\:rule}:\quad \left(a^b\right)^c=a^{bc},\:\quad \:a\ge 0](https://tex.z-dn.net/?f=%5Cmathrm%7BApply%5C%3Aexponent%5C%3Arule%7D%3A%5Cquad%20%5Cleft%28a%5Eb%5Cright%29%5Ec%3Da%5E%7Bbc%7D%2C%5C%3A%5Cquad%20%5C%3Aa%5Cge%200)
![\left(3^3\right)^{\frac{1}{3}}=3^{3\cdot \frac{1}{3}}](https://tex.z-dn.net/?f=%5Cleft%283%5E3%5Cright%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%3D3%5E%7B3%5Ccdot%20%5Cfrac%7B1%7D%7B3%7D%7D)
![=3^{3\cdot \frac{1}{3}}](https://tex.z-dn.net/?f=%3D3%5E%7B3%5Ccdot%20%5Cfrac%7B1%7D%7B3%7D%7D)
![=3^1](https://tex.z-dn.net/?f=%3D3%5E1)
![\mathrm{Apply\:exponent\:rule}:\quad \:a^1=a](https://tex.z-dn.net/?f=%5Cmathrm%7BApply%5C%3Aexponent%5C%3Arule%7D%3A%5Cquad%20%5C%3Aa%5E1%3Da)
![=3](https://tex.z-dn.net/?f=%3D3)
Therefore, the simplified value of the exponential expression is:
![27^{\frac{1}{3}}=3](https://tex.z-dn.net/?f=27%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%3D3)
Answer:
The answer is B. 132
Step-by-step explanation:
Answer:
168.
Step-by-step explanation:
H.C.F. = 6 = 2 by 3.
L.C.M. = 280 = 2^3 by 5 by 7.
30 = 2 by 3 by 5.
x = 2^3 by 3 by 7 = 168.
I used the factorisation method.