We must find UNIQUE combinations because choosing a,b,c,d... is the same as d,c,b,a...etc. For this type of problem you use the "n choose k" formula...
n!/(k!(n-k)!), n=total number of choices available, k=number of choices made..
In this case:
20!/(10!(20-10)!)
20!/(10!*10!)
184756
Answer:
Yes any number can be substituted for h
Step-by-step explanation:
The term 'h' is an independent variable any number can be substituted for h, so long as the number represents the hours worked
So if she walks pets for 8 hours
Her pay is 4*8= $32
Let the measure of side AB be x, then, the measue of side AE is given by

.
Now, ABCD is a square of size x, thus the area of square ABCD is given by

Also, AEFG is a square of size

, thus, the area of square AEFG is given by

<span>The sum of the areas of the two squares ABCD and AEFG is given by

Therefore, </span>the number of square units in the sum of the areas of the two squares <span>ABCD and AEFG is 81 square units.</span>
Answer:
- 20
Step-by-step explanation:
Total Change in enrollment = - 60
Period of time at which change occurred = 3 years
Average change per year :
Total change in enrollment / period at which change occurred
= - 60 / 3
= - 20
Average change of - 20 enrollments per year
A prime number<span> has only two factors: 1 and itself. A</span>composite number<span> has more than two factors. The</span>number<span> 1 is neither </span>prime<span> nor </span>composite<span>. The </span>prime numbers<span> between 2 and 31 are 2, 3, 5, 7, 11, 13, 17, 19, 23, 29 and 31 since each of these </span>numbers<span> has only two factors, itself and 1.</span>