All categories

3 years ago

Which integer represents 100 feet below sea level? A) 100 B) 0 C) −100 D) −200

Mathematics

2 answers:

alina1380 [7]3 years ago

7 0

Answer:

Step-by-step explanation:

-100

lana66690 [7]3 years ago

4 0

Answer:

c-100

Step-by-step explanation:

theoretically on the sea level its 0 and by going down by 100 it will be -100ft below the surface.

I hope this helps!!

You might be interested in

Write an expression that represents the height of a tree that begins at 10 feet and increases by 3 feet per year. Let t represen

mestny [16]

t represents number of years
initial height=10ft
Increases per year=3ft

Expression:-

$\\ \sf\longmapsto 10+3t$

3 0

3 years ago

3x + 2y = 12 y = x - 9

Lina20 [59]

Answer:

y=12/2

y=6

x=12/3

x=4

y= x-9

Y=4-9

y=5

6=5

6/5

1.2

5 0

3 years ago

First make a substitution and then use integration by parts to evaluate the integral. (Use C for the constant of integration.) x

e-lub [12.9K]

Answer:

$(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C$

Step-by-step explanation:

Ok, so we start by setting the integral up. The integral we need to solve is:

$\int x ln(5+x)dx$

so according to the instructions of the problem, we need to start by using some substitution. The substitution will be done as follows:

U=5+x

du=dx

x=U-5

so when substituting the integral will look like this:

$\int (U-5) ln(U)dU$

now we can go ahead and integrate by parts, remember the integration by parts formula looks like this:

$\int (pq')=pq-\int qp'$

so we must define p, q, p' and q':

p=ln U

$p'=\frac{1}{U}dU$

$q=\frac{U^{2}}{2}-5U$

q'=U-5

and now we plug these into the formula:

$\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int \frac{\frac{U^{2}}{2}-5U}{U}dU$

Which simplifies to:

$\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int (\frac{U}{2}-5)dU$

Which solves to:

$\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\frac{U^{2}}{4}+5U+C$

so we can substitute U back, so we get:

$\int xln(x+5)dU=(\frac{(x+5)^{2}}{2}-5(x+5))ln(x+5)-\frac{(x+5)^{2}}{4}+5(x+5)+C$

and now we can simplify:

$\int xln(x+5)dU=(\frac{x^{2}}{2}+5x+\frac{25}{2}-25-5x)ln(5+x)-\frac{x^{2}+10x+25}{4}+25+5x+C$

$\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}-\frac{5x}{2}-\frac{25}{4}+25+5x+C$

$\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C$

notice how all the constants were combined into one big constant C.

7 0

3 years ago

Can someone tell me how to do this! #2 & #4

torisob [31]

2) The area is 1.1 m^2 because to find the area the formula is width*length. SO you would separate it. It would be 0.9 * 1 = 0.9 and 0.4 * 0.5 = 0.2. Then you add it together. So it would be 1.1 m^2. The perimeter is all the sides added together so 4.2 m, but it says mm so you have to convert it and you get 4200.
4) Area is 1.16 cm^2. Again you would seperate it. So, 1 * 1 = 1 and .2 * .8 = .16. Then you add it together and get 1.16 cm^2. The perimeter is all the sides added up. You get 4.2 cm.

8 0

3 years ago

Read 2 more answers

Will give brainliest please help 4b + 7b +5 i need help simplifying.

vitfil [10]

Answer:

11b+5

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers