Question

Given a mean of 7.6 and a standard deviation of 3.1, what is the z-score of the value 5 rounded to the nearest tenth?

Answer 1

Given mean μ = 7.6 and standard deviation σ =3.1

The z score value for x= 5 is given by

Z = $\frac{x - mean}{standard deviation}$

Z = $\frac{5 - 7.6}{3.1 }$

Z = -0.8387

The Z- score value rounded to nearest tenth is -0.8

The correct answer choice is A. -0.8