Miguel stated that any monomial can be a cube root. Sylvia disagreed and said that a monomial cube root must have exponents divi sible by 3. Who is correct, and why? A) Sylvia is correct. Any variable term, when it is cubed, always has an exponent divisible by 3.
B) Miguel is correct. Any monomial can be a perfect cube root because, when it is cubed, the variables will have exponents divisible by 3.
C) Sylvia is correct. In order for the cube to have exponents that are divisible by 3, the cube root has to be divisible by 3.
D)Miguel is correct. Sylvia confused the perfect square root with the perfect cube root.
1 answer:
Answer:
B. Miguel is correct. Any monomial can be a perfect cube root because, when it is cubed, the variables will have exponents divisible by 3.
Step-by-step explanation:
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Answer:
see below
Step-by-step explanation:
Since RT bisects QRS
1/2 QRS = TRS
1/2 ( 9x+214) = -9x+53
Multiply each side by 2
9x +214 = -18x+ 106
Add 18x from each side
9x +214+18x = 106
27x +214 = 106
Subtract 214 from each side
27x = 106-214
27x =-108
Divide by 27
27x/27 = -108/27
x = -4
TRS = -9x+53
=-9 *-4 +53
= 36+ 53
=89
Answer:
domain: (-4,4)
Step-by-step explanation:
i'm not sure if it has brackets because it doesn't have point that are on x-intervals -4 and 4
Answer:
(2,2) is your answer :)
Step-by-step explanation:
5p + 30 = 12p <== ur equation 5p - 12p = -30 -7p = -30 p = -30/-7 p = 4 2/7 pies to break even
Yes, because they both have the same slope, and a translation doesn't have an affect of the slope. Both slopes are 1, because they are going +1x and +1y, or 1/1 which = 1.