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Morgarella [4.7K]
4 years ago
7

Miguel stated that any monomial can be a cube root. Sylvia disagreed and said that a monomial cube root must have exponents divi

sible by 3. Who is correct, and why?
A) Sylvia is correct. Any variable term, when it is cubed, always has an exponent divisible by 3.

B) Miguel is correct. Any monomial can be a perfect cube root because, when it is cubed, the variables will have exponents divisible by 3.

C) Sylvia is correct. In order for the cube to have exponents that are divisible by 3, the cube root has to be divisible by 3.

D)Miguel is correct. Sylvia confused the perfect square root with the perfect cube root.
Mathematics
1 answer:
Pepsi [2]4 years ago
7 0

Answer:

B. Miguel is correct. Any monomial can be a perfect cube root because, when it is cubed, the variables will have exponents divisible by 3.

Step-by-step explanation:

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Helpp me asapp with this problem plss will crown brainiest !!!!
Evgen [1.6K]

Answer:

see below

Step-by-step explanation:

Since RT bisects QRS

1/2  QRS = TRS

1/2 ( 9x+214) = -9x+53

Multiply each side by 2

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Add 18x from each side

9x +214+18x = 106

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Subtract 214 from each side

27x = 106-214

27x =-108

Divide by 27

27x/27 = -108/27

x = -4

TRS = -9x+53

     =-9 *-4 +53

     = 36+ 53

    =89

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3 years ago
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Answer:

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Step-by-step explanation:

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4 years ago
Need help with this answer
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Step-by-step explanation:

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3 years ago
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