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astraxan [27]
3 years ago
8

HELP! Find x. Round to the nearest tenth. 64 8

Mathematics
1 answer:
alina1380 [7]3 years ago
4 0

Answer:

x= 3.5 (nearest tenth)

Step-by-step explanation:

Please see the attached picture for the full solution.

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85×250=_______ + 387= _______
Neko [114]

Answer:

21,637

Step-by-step explanation:

You can just use a caculator- Or simple multiplication by putting it on top of eachother.

You can do this many ways,just multiply with pen and paper,put 250 on top,and 85 on bottom which is 21,250,the add from there!

Hope I helped!!

7 0
2 years ago
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Which expression is equivalent to x2 - 8x + 15​
Valentin [98]
The answer is ( x - 3 ) ( x - 5)
3 0
3 years ago
HELP PLEASE!!!!!!!!!!!!!!!!!!!! I NEED IT ASAP!!!!!!!!!
FinnZ [79.3K]
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4 0
2 years ago
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For the years from 2002 and projected to 2024, the national health care expenditures H, in billions of dollars, can be modeled b
dmitriy555 [2]

Answer:

2019.

Step-by-step explanation:

We have been given that for the years from 2002 and projected to 2024, the national health care expenditures H, in billions of dollars, can be modeled by H = 1,500e^{0.053t} where t is the number of years past 2000.

To find the year in which national health care expenditures expected to reach $4.0 trillion (that is, $4,000 billion), we will substitute H=4,000 in our given formula and solve for t as:

4,000= 1,500e^{0.053t}

\frac{4,000}{1,500}=\frac{ 1,500e^{0.053t}}{1,500}

\frac{8}{3}=e^{0.053t}

e^{0.053t}=\frac{8}{3}

Take natural log of both sides:

\text{ln}(e^{0.053t})=\text{ln}(\frac{8}{3})

0.053t\cdot \text{ln}(e)=\text{ln}(\frac{8}{3})

0.053t\cdot (1)=0.9808292530117262

\frac{0.053t}{0.053}=\frac{0.9808292530117262}{0.053}

t=18.506212320

So in the 18.5 years after 2000 the expenditure will reach 4 trillion.

2000+18.5=2018.5

Therefore, in year 2019 national health care expenditures are expected to reach $4.0 trillion.

7 0
4 years ago
Can someone please please please, help me this is my last page and I’ve been stuck on an hour and a half can someone Plz help me
My name is Ann [436]

Answer:

sorry I can't heheh just came to see but it's math you know search on browser one by one I'm sure you can find

6 0
3 years ago
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