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Rudik [331]
3 years ago
15

A survey asked eight students about their scores on a history test and whether they studied for the test. The table shows the re

sults of the survey.
Test Scores
Studied
Did Not Study
88
34
90
67
86
80
96
59


Which statements about the data sets are true? Check all that apply.
The mean absolute deviation for the group of students who studied is 12.
The mean absolute deviation for the group of students who did not study is 13.5.
The data for the group that studied are more spread out than the data for the group that did not study.
The data for the group that did not study are more spread out than the data for the group that studied.
The data for the group that studied are more clustered around the mean than the data for the group that did not study.
The data for the group that did not study are more clustered around the mean than the data for the group that did study.
Mark this and return
Mathematics
1 answer:
TEA [102]3 years ago
5 0
8274 obviously ushrisn usbe
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Check all of the correct solutions to this problem
MA_775_DIABLO [31]

To solve a quadratic equation ax^2+bx+c=0 we can use the quadratic formula:

x_{1,2} = \cfrac{-b\pm\sqrt{b^2-4ac}}{2a}

In your case, the equation is identified by a=c=1,\ b=-5

So, the solving formula yields

x_{1,2} = \cfrac{5\pm\sqrt{25-4}}{2} = \cfrac{5\pm\sqrt{21}}{2}

So, the two solutions are derived by choosing the plus sign once, and the minus sign the other time:

x_{1} = \cfrac{5+\sqrt{21}}{2},\quad x_{2} = \cfrac{5-\sqrt{21}}{2}

8 0
3 years ago
Solve а) 3х - 5 = 13​
skelet666 [1.2K]

Answer:

6

Step-by-step explanation:

3х - 5 = 13

     +5   +5

3x=18

/3   /3

x=6

3 0
3 years ago
I will give brilleent 4 the right answer
lord [1]

Answer:

tell me the question i will try my best to solve it

7 0
3 years ago
Which equation represents a line that passes through (5, 1) and has a slope of 1/2<br> ?
Illusion [34]
Y-y1=m(x-X1) is the formula.
m is the slope and the y1 and x1 are your points. 
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When x = 8, y = 12. Find y when x = 80
gtnhenbr [62]

Can you give an equation


5 0
3 years ago
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