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alekssr [168]
3 years ago
6

The width of a rectangle is 4 inches greater than half the length. The perimeter is 56 inches. What is the length and the width

of the rectangle
Mathematics
2 answers:
yulyashka [42]3 years ago
7 0

Answer:

Length of the rectangle = 16 inches

Width of the rectangle = 12 inches

Step-by-step explanation:

Let the length of the rectangle be represented by x.

Then width can be expressed as \[\frac{x}{2}+4\]


Perimeter of a rectangle is the sum of four sides of the rectangle.

This can be expressed as 2*(length + breadth)

= \[2* (x + \frac{x}{2}+4)\]

= \[2* (\frac{3x}{2}+4)\]

= \[3x + 8\]

But perimeter is given as 56.

So, \[3x + 8 = 56\]


=> \[3x = 48\]

=> \[x = 16\]

Hence length of the rectangle = 16 inches

Width of the rectangle = \[\frac{16}{2}+4\] = 12 inches

RoseWind [281]3 years ago
7 0

Answer:

length = 16 inches and width = 12 inches

Step-by-step explanation:

Let l be the length and w be the width of the rectangle.

It is given that width is 4 inches greater than half of the length:

w=\frac{l}{2}+4 ------1

Perimeter of the rectangle is given by 2\times(l+w)

2\times(l+w)=56

l+w=28  ----------------2

Substituting w from equation 1 in equation 2, we get:

l+(4+\frac{l}{2})=28

\frac{3l}{2}=24

∴ l = 16 inches

Putting l=16 in equation 1, we get w=12.

Hence w= 12 inches.

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Answer:

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and continuity correction factor is used when a continuous probability distribution is used on a discrete probability distribution

Step-by-step explanation:

An example of when a continuity correction factor can be used is in finding the number of tails in 50 tosses of a coin within a given range .

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compute the projection of → a onto → b and the vector component of → a orthogonal to → b . give exact answers.
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\text { Saclar projection } \frac{1}{\sqrt{3}} \text { and Vector projection } \frac{1}{3}(\hat{i}+\hat{j}+\hat{k})

We have been given two vectors $\vec{a}$ and $\vec{b}$, we are to find out the scalar and vector projection of $\vec{b}$ onto $\vec{a}$

we have $\vec{a}=\hat{i}+\hat{j}+\hat{k}$ and $\vec{b}=\hat{i}-\hat{j}+\hat{k}$

The scalar projection of$\vec{b}$onto $\vec{a}$means the magnitude of the resolved component of $\vec{b}$ the direction of $\vec{a}$ and is given by

The scalar projection of $\vec{b}$onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|}$

$$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\sqrt{1^2+1^1+1^2}} \\&=\frac{1^2-1^2+1^2}{\sqrt{3}}=\frac{1}{\sqrt{3}}\end{aligned}$$

The Vector projection of $\vec{b}$ onto $\vec{a}$ means the resolved component of $\vec{b}$ in the direction of $\vec{a}$ and is given by

The vector projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|^2} \cdot(\hat{i}+\hat{j}+\hat{k})$

$$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\left(\sqrt{1^2+1^1+1^2}\right)^2} \cdot(\hat{i}+\hat{j}+\hat{k}) \\&=\frac{1^2-1^2+1^2}{3} \cdot(\hat{i}+\hat{j}+\hat{k})=\frac{1}{3}(\hat{i}+\hat{j}+\hat{k})\end{aligned}$$

To learn more about scalar and vector projection visit:brainly.com/question/21925479

#SPJ4

3 0
1 year ago
Can you use elimination to solve a system of linear equations with three equations
crimeas [40]
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Archy [21]

Answer:

b

Step-by-step explanation:

In general

Given

y = f(x) then y = f(Cx) is a horizontal stretch/ compression in the x- direction

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Consider corresponding points on the 2 graphs

(2, 2 ) → (4, 2 )

(4, - 2 ) → (8, - 2 )

Indicating a stretch in the x- direction.

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stretches the graph in the x- direction by a factor of 2

Thus

y = f(\frac{x}{2} ) → b

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