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deff fn [24]
3 years ago
5

How do you solve :

Formula1" title="x {}^{2} = \frac{2}{3} " alt="x {}^{2} = \frac{2}{3} " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Neporo4naja [7]3 years ago
5 0

x^2=\dfrac{2}{3}\to x=\pm\sqrt{\dfrac{2}{3}}\\\\x=-\dfrac{\sqrt{2}}{\sqrt3}\ \vee\ x=\dfrac{\sqrt2}{\sqrt3}\\\\x=-\dfrac{\sqrt2\cdot\sqrt3}{\sqrt3\cdot\sqrt3}\ \vee\ x=\dfrac{\sqrt2\cdot\sqrt3}{\sqrt3\cdot\sqrt3}\\\\\boxed{x=-\dfrac{\sqrt6}{3}\ \vee\ x=\dfrac{\sqrt6}{3}}

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Solve each word problem using a system of equations. Use substitution or elimination.
nasty-shy [4]

Answer:

Step-by-step explanation:

x + 3y = 24.....multiply by -1

5x + 3y = 36

------------------

-x - 3y = -24 (result of multiplying by -1)

5x + 3y = 36

------------------add

4x = 12

x = 12/4

x = 3 <=======

x + 3y = 24

3 + 3y = 24

3y = 24 - 3

3y = 21

y = 21/3

y = 7 <========

4 0
3 years ago
Please help me out with this!!<br> BRAINLIEST AVAILABLE!!
lapo4ka [179]

Answer:

xy = 1

k = 79

Step-by-step explanation:

Question One

The first and third frames look to me to be the same. I'll treat them that way.

y = x^2                        Equate y = x^2 to the result of 2y + 6 = 2x + 6

2y + 6 = 2(x + 3)         Remove the brackets

2y + 6 = 2x + 6           Subtract 6 from both sides

2y = 2x                       Divide by 2

y = x

Now solve these two equations.

so x^2 = x                  

x > 0

1 solution is x = 0 from which y = 0. This won't work. x must be greater than 0. So the other is

x(x) = x                           Divide both sides by x            

x = 1                            

y = x^2                           Put x = 1 into x^2

y = 1^2                           Solve

y = 1                      

The second solution is

(1,1)

xy = 1*1

xy = 1

Answer: A

Question Two

square root(k + 2) - x = 0

Subtract x from both sides

sqrt(k + 2) = x                Square both sides

k + 2 = x^2                    Let x = 9

k + 2 = 9^2                    Square 9

k + 2 = 81

k = 81 - 2

k = 79

4 0
3 years ago
An ivy contains 5 mg of drug per ml and the patient needs to receive 100mg per hour what is the infusion in ml/hr
SashulF [63]

Answer:

patient is going to need to get 100ml/hr

7 0
3 years ago
is this answer correct? if not please explain. The question is “The mass of the Eock of Gibraltar is 1.78 • 10 power of 12 kilog
Natalija [7]

Answer:

Step-by-step explanation:

Mass of Antarctic iceberg - Mass of Rock Gibraltar=

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Answer: 43.72 * 10^12 kg

3 0
3 years ago
Olympia Hospital has overall variable costs of 25% of total revenue and fixed costs of $45 million
blagie [28]
  1. In terms of total revenue, the break-even point of Olympia Hospital is equal to $60 millions.
  2. The average daily revenue per patient-day that is necessary to achieve the break-even total revenue is $1,600.

<h3>What is the break-even analysis?</h3>

Break-even analysis is also referred to as cost-volume-profit analysis and it can be defined as a financial accounting technique that is used to determine the number of units (products) which a business firm must sell at a specific price, either on a monthly or annual basis, so as to cover all of its costs.

<h3>How to calculate the break-even point?</h3>

In terms of total revenue, the break-even point of Olympia Hospital can be calculated by using this formula:

Break-even point = Fixed cost/CM ratio

Break-even point = $45 million/(100% - 25%)

Break-even point = $45 million/75%

Break-even point = $45 million/0.75

Break-even point = $60 millions.

<h3>How to calculate the average daily revenue?</h3>

Average daily revenue = Break-even point/Number of patient-days

Average daily revenue = $60 millions/37,500

Average daily revenue = $1,600.

Read more on break-even analysis here: brainly.com/question/20973795

#SPJ1

4 0
2 years ago
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