X=width of a coccer pitch
2x-20=length of a soccer pitch
Area (rectangule)=length x width
We suggest this equation:
x(2x-20)=6000
2x²-20x=6000
2x²-20x-6000=0
x²-10x-3000=0
We solve this quadratic equation:
x=[10⁺₋√(100-4*1*-3000)]/2=[10⁺₋√(100+12000)]/2=
=(10⁺₋110)/2
we have two solutions:
x₁=(10-110)/2=-50, invalid solution.
x₂=(10+110)/2=60
x=60
2x-20=2(60)-20=120-20=100
Solution: the length is 100 m, and the width is 60 m.
To check:
Area=100 m*60 m=6000 m²
The twice of width is =2(60 m)=120 m,
20 m less than twice its width is: 120 m-20 m=100 m=the length.
When x = - 4 then
y = 1/2(-4) -6
y = -2 - 6
y = -8
solution (-4, -8)
answer is
B. (-4, -8) second choice
We are going to find the plot where this coordinates are in the graph.
Your graph will be in the attachment below.
~Jurgen
Answer:
Distributive Property : <em><u>a(b+c)= ab+ac</u></em>
<h3><u>(35-28x)</u> is the right answer.</h3>
The answer is 148, what grade are you in that’s really easy unless you didn’t pay attention. , anyways keep up
