Answer:
(A) 
(b) 
(c) 
(d) 
Step-by-step explanation:
We have given expression and we have to simplify the expression using exponent property
(A) 
So 
(b) 
So 
(c) 
So 
(d) 
Answer:
B
Step-by-step explanation:
So we have the formula:

And we want to solve it for r.
So, let's first divide both sides by π and h. This will cancel out the right side:

Now, take the square root of both sides:

And we're done!
Our answer is B.
I hope this helps!
By definition, the number
is the ratio between the circumference and the diameter:

This implies that

And so your circumference is 
Answer:

Step-by-step explanation:
First FOIL (n + 7)(n + 8) and then distribute n
(n + 7)(n + 8) = 
n (
)
= 
Answer:
wait are you the person who is putting lyrics of a certain song? oh yeah it is! hello
Step-by-step explanation: