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Romashka-Z-Leto [24]
2 years ago
12

An educational psychologist wishes to know the mean number of words a third grader can read per minute. She wants to make an est

imate at the 95% level of confidence. For a sample of 695 third graders, the mean words per minute read was 38.3. Assume a population standard deviation of 3.6. Construct the confidence interval for the mean number of words a third grader can read per minute. Round your answers to one decimal place.
Mathematics
1 answer:
amid [387]2 years ago
8 0

Answer:

(38.1,88.6)

Step-by-step explanation:

We are given the following in the question:

Sample mean, \bar{x} = 38.3

Sample size, n = 695

Alpha, α = 0.05

Population standard deviation, σ = 3.6

95% Confidence interval:

\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}

Putting the values, we get,

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

38.3 \pm 1.96(\frac{3.6}{\sqrt{695}} ) = 38.3 \pm 0.267 = (38.033,38.567) \approx (38.1,88.6)

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An object is acted upon by the forces F1=<10​,6​,4> and F2=<0​,3​,9>. Find the force F3 that must act on the object
murzikaleks [220]

\vec F_3=\langle x,y,z\rangle is a force vector such that

\vec F_1+\vec F_2+\vec F_3=\vec0

\implies\langle10,6,4\rangle+\langle0,3,9\rangle+\langle x,y,z\rangle=\langle0,0,0\rangle

\implies\begin{cases}10+x=0\\9+y=0\\13+z=0\end{cases}\implies x=-10,y=-9,z=-13

So the missing force is

\boxed{\vec F_3=\langle-10,-9,-13\rangle}

8 0
2 years ago
Can anyone help with this?
4vir4ik [10]
SAS is the true answer
6 0
2 years ago
Machine A produces bolts at a uniform rate of 120 every 40 seconds, and Machine B produces bolts at a uniform rate of 100 every
Nutka1998 [239]

Answer:

25 seconds

Step-by-step explanation:

Hi there!

In order to answer this question, first we need to know how many bolts per second are produced by each machine, this can be known by dividing the number of bolts by the time it takes.

For machine A:

A = \frac{120 bolts}{40 s}= 3 \frac{bolts}{s}

For machine B:

B = \frac{100 bolts}{20 s}= 5 \frac{bolts}{s}

So, if the two machines run simultaneously, we will have a rate of prodcution of bolts equal to the sum of both:

A+B=(3+5)\frac{bolts}{s}=8\frac{bolts}{s}

Now, we need to know how much time it will take to producee 200 bolts, to find this out we need to divide the amount of bolts by the production rate:

t = \frac{bolts}{ProductionRate}= \frac{200 bolts}{8 \frac{bolts}{s} }

The <em>bolts</em> unit cancell each other and we are left with <em>seconds</em>

t = \frac{200}{8} s = 25 s

So it will take 25 seconds to produce 200 bolts with machine A and B running simultaneously.

Greetings!

4 0
3 years ago
Read 2 more answers
1250 / 16 show work please answer fast
OLga [1]

Answer:

78.125

Step-by-step explanation:

sorry i can show the work :(

5 0
2 years ago
Evaluate the expression
larisa86 [58]

Answer:

12-[20-2(6^2\div3\times2^2)]=88

Step-by-step explanation:

So we have the expression:

12-[20-2(6^2\div3\times2^2)]

Recall the order of operations or PEMDAS:

P: Operations within parentheses must be done first. On a side note, do parentheses before brackets.

E: Within the parentheses, if exponents are present, do them before all other operations.

M/D: Multiplication and division next, whichever comes first.

A/S: Addition and subtraction next, whichever comes first.

(Note: This is how the order of operations is traditionally taught and how it was to me. If this is different for you, I do apologize. However, the answer should be the same.)

Thus, we should do the operations inside the parentheses first. Therefore:

12-[20-2(6^2\div3\times2^2)]

The parentheses is:

(6^2\div3\times2^2)

Square the 6 and the 4:

(36\div3\times4)

Do the operations from left to right. 36 divided by 3 is 12. 12 times 4 is 48:

(36\div3\times4)\\=(12\times4)\\=48

Therefore, the original equation is now:

12-[20-2(6^2\div3\times2^2)]\\=12- [20-2(48)]

Multiply with the brackets:

=12-[20-96]

Subtract with the brackets:

=12-[-76]

Two negatives make a positive. Add:

=12+76=88

Therefore:

12-[20-2(6^2\div3\times2^2)]=88

3 0
3 years ago
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