Answer:
A = 3E
A + E = 56
3E + E = 56
4E = 56
E = 14
Elga is 14 years old.
Step-by-step explanation:
Could you please mark me as the brainliest answer
x = 15 and y = 12
4x + 2 = 62 ( alternate congruent angles )
subtract 2 from each side
4x = 60 ( divide both sides by 4 )
x = 15
12y = 144 ( alternate congruent angles )
divide both sides by 12
y = 12
Answer:
-1
Step-by-step explanation:
f(x) =2/3x -5
Let x = 6
f(6) = 2/3 (6) - 5
Multiply first
f(6) = 12/3 -5
= 4-5
= -1
The equation given is
where a is some number.
We can solve for x by taking the square root of both sides.
Now let's think through what happens for various values of a.
TWO SOLUTIONS
If a is a positive number the above yields two solutions. Take for example:
There will be two solutions (one positive and one negative) as there are two numbers (here -7 and +7) that when multiplied by themselves give 49. That is,
and
. The positive root is called the principal root and the negative root is called the secondary root. This will be the case anytime we take the root of a positive number.
ONE SOLUTION
If a = 0 there is only one solution. That is because
and
. Zero is neither positive nor negative and it has only one root which is 0 itself. So in this case there is only one solution and it is 0.
NO (REAL) SOLUTIONS
If a is negative we would be taking the square root of a negative number. There is no (real) number that when multiplied by itself gives a negative number. Take for example
which gives us
. The square root of -49 is not 7 because (7)(7)=49 which is positive. The square root of -49 is not -7 because (-7)(-7)=49 which is also positive. There is no real number that gives -49 when multiplied by itself. I say "real" numbers because there do exist imaginary/complex numbers but because of the way the questions was asked I imagine you may not know about these yet.