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4 years ago

Which of the following is a area of the special trepezoid if ab=19,cd=19 and the height is 14

Mathematics

1 answer:

tankabanditka [31]4 years ago

5 0

As, Opposite side of Special trapezoid is equal.So, it will be a Parallelogram.

ab=c d= 19 units

Height of Trapezoid = 14 units

Area of Trapezoid = $\frac{1}{2} \times {\text{Sum of parallel sides}} \times {\text{Perpendicular Distance between them}}$

$=\frac{1}{2}\times (19+19) \times 14\\\\ =\frac{1}{2} \times 38 \times 14\\\\ = 19 \times 14\\\\= 266$

So, Area of Trapezoid = 266 square units

You, can use the formula for finding the area of parallelogram,which is = Base on which perpendicular is drawn × Length of Altitude

= 19 × 14

= 266 square units

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4th grade math question Joey walk 333 ft how many yards did Joey walk? At 5 yds vs 15 ft

icang [17]

111 yards

Explanation

Step 1

to solve this we need to know the equivalence

$\begin{gathered} 3\text{ ft= 1 yd} \\ 3\text{ ft}\leftrightarrow1\text{ yd} \end{gathered}$

Now, we can apply a rule of three

let x represents the number of yards in 333 ft, so

$\begin{gathered} if \\ 3\text{ ft}\rightarrow\text{ 1 yd} \\ \text{then} \\ 33\text{ ft}\rightarrow x \end{gathered}$

as the ratio is the same, we have a proportion

$\begin{gathered} \frac{3\text{ ft}}{1\text{ yd}}=\frac{33\text{ ft}}{x\text{ yd}} \\ \frac{3}{1}=\frac{33}{x} \end{gathered}$

Step 2

now, solve for x

$\begin{gathered} \frac{3}{1}=\frac{333}{x} \\ \text{cross multiply} \\ 3\cdot x=333\cdot1 \\ 3x=333 \\ \text{divide both } \\ \frac{3x}{3}=\frac{333}{3} \\ x=111 \end{gathered}$

so, the answer is 111 yards

I hope this helps you

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1 year ago

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3 years ago

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Bess [88]

Answer:

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Step-by-step explanation:

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Multiply the first terms
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Let's do the steps on our problem:

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Listing the terms, we have: 3x^2 -4x + 27x - 36

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4 years ago

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Rama09 [41]

Answer:

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Step-by-step explanation:

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s344n2d4d5 [400]

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Step-by-step explanation:

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3 years ago

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