Question

Which of the following is a area of the special trepezoid if ab=19,cd=19 and the height is 14

Answer 1

As, Opposite side of Special trapezoid is equal.So, it will be a Parallelogram.

ab=c d= 19 units

Height of Trapezoid = 14 units

Area of Trapezoid =  $\frac{1}{2} \times {\text{Sum of parallel sides}} \times {\text{Perpendicular Distance between them}}$

  $=\frac{1}{2}\times (19+19) \times 14\\\\ =\frac{1}{2} \times 38 \times 14\\\\ = 19 \times 14\\\\= 266$

So, Area of Trapezoid = 266 square units

You, can use the formula for finding the area of parallelogram,which is = Base on which perpendicular is drawn × Length of Altitude

= 19 × 14

= 266 square units