Answer:
1. = 3xy + x - 2y - 4
2. = d^2(2c^3-8c^2d+3d^2)
Step-by-step explanation:
= 9x^2y^2 + 3x^2y - 6xy^2 - 12xy/3xy
First factor the top equation ….
= 3xy(3xy + x - 2y - 4)/3xy
If the top and the bottom both carry 3xy, you can cancel out both of them leaving you with ….
= 3xy + x - 2y - 4
= -16c^6d^6 + 64c^5d^7 - 24c^3d^8/-8c^3d^4
First factor the top equation ....
= -8c^3d^6(2c^3-8c^2d+3d^2)/-8c^3d^4
If the top and the bottom both carry -8c^3 you can cancel out both of them leaving you with ….
= <u>d^6</u>(2c^3-8c^2d+3d^2)/d^4
Apply the exponent rule with d^6 ....
= <u>d^4</u><u>d^2</u>(2c^3-8c^2d+3d^2)/d^4
cancel out d^4 ....
= d^2(2c^3-8c^2d+3d^2)
Answer:
a) 3x - 1
Step-by-step explanation:
f(x) + g(x)
(-2x + 6) + (5x - 7)
Drop the parentheses
-2x + 6 + 5x -7
5x and -2x can be combined as well as 6 and -7
So, 3x -1
Answer:
At least 75% of these commuting times are between 30 and 110 minutes
Step-by-step explanation:
Chebyshev Theorem
The Chebyshev Theorem can also be applied to non-normal distribution. It states that:
At least 75% of the measures are within 2 standard deviations of the mean.
At least 89% of the measures are within 3 standard deviations of the mean.
An in general terms, the percentage of measures within k standard deviations of the mean is given by 
.
In this question:
Mean of 70 minutes, standard deviation of 20 minutes.
Since nothing is known about the distribution, we use Chebyshev's Theorem.
What percentage of these commuting times are between 30 and 110 minutes
30 = 70 - 2*20
110 = 70 + 2*20
THis means that 30 and 110 minutes is within 2 standard deviations of the mean, which means that at least 75% of these commuting times are between 30 and 110 minutes
Thats uhhhhhh..... thats pretty cool.
Answer:
Step-by-step explanation:
y = 3x + 2
6x – 2y = 10
Ryan’s answer:
I solved by adding the equations. The solution is .
y = 3x + 2 → 3x + y = 2
6x – 2y = 10 → 3x – y = 5
6x = 7
x =
6x – 2y = 10 → 6 – 2y = 10
7 – 2y = 10
–2y = –3
y = -
Jesse’s answer:
I used matrices. The solution is .
Mark’s answer:
I graphed the equations. The lines are parallel and do not intersect, so there is no solution.
