All categories

2 years ago

a tree 20 feet tall with a circumference of 3 ft has a vine wound around 7 times. How long is the vine?

Mathematics

2 answers:

marin [14]2 years ago

6 0

The length of the vine is 21 ft

what is the circumference of a circle?

the circumference is the perimeter of a circle

the perimeter of the circle = 2πr = 3 ft

the vine is 7 times the perimeter

length of vine = 7×3= 21 ft

learn more on circumference here :

brainly.com/question/20489969

#SPJ1

FinnZ [79.3K]2 years ago

4 0

If the tree is 20 feet tall with circumference 3 feet then the length of vince is around 21 feet.

Given the height of tree is 20 feet and the circumference of tree is 3 feet.

We have to find the length of vine.

Circumference is the perimeter of a circular object. Because the trunk of a tree is in shape of circle so the perimeter of the trunk is 2πr.

We have been given the circumference of tree be 3 feet.

Circumference=2πr

Because vine is 7 times the circumference so the length of vine being:

Length of vine=7*3

=21 feet.

Hence if the tree is 20 feet tall with circumference 3 feet then the vince is around 21 feet long.

Learn more about circumference at brainly.com/question/20489969

#SPJ1

You might be interested in

Please Help me answer all 4 questions with a full explanation so I can solve the rest on my own.

Nata [24]

$\\ \rm\Rrightarrow (2x^2)^3.2yx^0=8x^6.2y=16x^6y$

$\\ \rm\Rrightarrow (2x^4y^3)^3.2x^4y^4=8x^{12}y^6.2x^4y^4=16x^{16}y^{10}$

$\\ \rm\Rrightarrow (m^3n^0(2m^3n^2)^4)^2=(m^316m^{12}n^8)^2=(16m^{15}n^8)^2=256m^{30}n^{16}$

$\\ \rm\Rrightarrow (2xy^3)^2.2x^2y^0=4x^2y^6.2x^2=8x^4y^6$

6 0

2 years ago

Please help show work too please thank you

Black_prince [1.1K]

(3x-9) +(x+19)+x=180
5x+10=180
-10=-10
5x=170
5 = 5
x=34

2x+(2x+10)+x=180
5x+10=180
-10=-10
5x=170
5 = 5
x=34

yes they are similar

6 0

3 years ago

Solve for x in the equation x2 - 12x+36 = 90.

cupoosta [38]

Answer:

<u>The correct answer is A. x = 6 + 3 √10</u>

Step-by-step explanation:

Let's solve for x:

x² - 12x + 36 = 90

Factoring this quadratic equation, we have:

(x - 6) (x - 6) = 90

(x - 6)² = 90

x - 6 = √90 (Square root to both sides of the equation)

x = 6 + √90 (Adding 6 to both sides of the equation)

x = 6 + √9 * 10

x = 6 + √3² * 10

x = 6 + 3 √10

<u>The correct answer is A. x = 6 + 3 √10</u>

5 0

3 years ago

The sum of 3 times m and 4 times m

drek231 [11]

Answer:

7 meters

Step-by-step explanation:

(3*m) + (4*m)

7 meters

5 0

3 years ago

Read 2 more answers

The polar curve $r = 1 + \cos \theta$ is rotated once around the point with polar coordinates $(2,0).$ What is the area of the r

mash [69]

Answer:

$Area = -2.3147$

Step-by-step explanation:

Given

$r = 1 + \cos \theta$

Required

Determine the area with coordinates $(2,0)$

The area is represented as:

$Area = \frac{1}{2}\int\limits^b_a {r^2} \, d\theta$

Where

$r = 1 + \cos \theta$

and

$(a,b) = (2,0)$

Substitute values for r, a and b in

$Area = \frac{1}{2}\int\limits^b_a {r^2} \, d\theta$

$Area = \frac{1}{2}\int\limits^0_2 {(1 + cos\theta)^2} \, d\theta$

Expand

$Area = \frac{1}{2}\int\limits^0_2 {(1 + cos\theta)(1 + cos\theta)} \, d\theta$

$Area = \frac{1}{2}\int\limits^0_2 {(1 + 2cos\theta+cos^2\theta} )\, d\theta$

By integratin the above, we get:

$Area = \frac{1}{2}*\frac{(cos(\theta) + 4)sin(\theta) + 3\theta}{2}[0,2]$

$Area = \frac{(cos(\theta) + 4)sin(\theta) + 3\theta}{4}[0,2]$

Substitute 0 and 2 for $\theta$ one after the other

$Area = \frac{(cos(0) + 4)sin(0) + 3*0}{4} - \frac{(cos(2) + 4)sin(2) + 3*2}{4}$

$Area = \frac{(cos(0) + 4)sin(0)}{4} - \frac{(cos(2) + 4)sin(2) + 6}{4}$

$Area = \frac{(1 + 4)*0}{4} - \frac{(cos(2) + 4)sin(2) + 6}{4}$

$Area = - \frac{(cos(2) + 4)sin(2) + 6}{4}$

$Area = \frac{-sin(2)(cos(2) + 4) - 6}{4}$

Get sin(2) and cos(2) in radians

$Area = \frac{-0.9093 * (-0.4161 + 4) - 6}{4}$

$Area = \frac{-9.2588}{4}$

$Area = -2.3147$

3 0

2 years ago