I'm going to do elimination to find the price of one pear and one orange.
6p +5o =1.87
12p + 2o=1.90
I'm going to multiply the first equation by -2.
-12p-10o = -3.74
12p + 2o =1.90
-8o= -1.84
-1.84÷ -8= .23= o
12p + 2 (.23) = 1.90
12p + .46 = 1.90
12p = 1.44
p=.12
A pear equals .12, while an orange equals .23.
3×.12= .36
.23× 3 = .69
.69 + .36 = 1.05
It would cost $1.05.
Answer:
First, 6 + 1 is 7, so 216p^7 is 219,369p
Step-by-step explanation:
Answer:
Step-by-step explanation:
3C + 8T = 58 ----- (eq1)
5C + 2T = 23 ------(eq2)
Multiply equation (1) by 5 and equation (2) by 3
15C + 40T = 290 -----(eq3)
15C + 6T = 69 ----------(eq4)
Subtract equation (4) from (3)
34T = 221
T = 221/34
T = $6.5
Therefore 1 Table will cost $6 and 5 cents
Solve for (C) in equation (1)
3C + 8T = 58
3C + 8(6.5) = 58
3C + 52 = 58
3C = 58-52
3C = 6
C = 6/3
C = $2
1 Chair will cost $2
The answer is 15
good night
Wouldn't it be 5000+500+0.600+0.040.
