I need help pls and thank you
1 answer:
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Answer:
The margin of error is of 0.038 = 3.8%.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of .
For this problem, we have that:
90% confidence level
So , z is the value of Z that has a pvalue of
, so
.
The margin of error is:
The margin of error is of 0.038 = 3.8%.