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erma4kov [3.2K]
3 years ago
5

Stacey Steady pays $19.95 per month for her fitness center membership. If she works out twice a week for a year, how much does s

he pay for each visit?
Mathematics
2 answers:
konstantin123 [22]3 years ago
7 0
Multiply the cost per month of $19.95 times 12 months.

12 * 19.95 = $239.40

Multiply the number of weeks in a year which is 52 by the number of visits per week which is 2.

2 * 52 = 104 visits

Divide the amount of money for the year ($239.40) by the number of visits (104).

$239.40 / 104 = $2.3019 per visit or rounded to $2.30.
zvonat [6]3 years ago
3 0

Answer:

2.30

Step-by-step explanation:

odyssey ware

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Factorise the following expressions.<br> a) 6x + 5x + 1<br> b) 6x2 13x + 6
fredd [130]

Answer:

a) 1 1 + 1

b)1 3 + 1 8

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Please explain step by step worth 20 points
ankoles [38]
Multipy $275 by the 4.5%
4.5%=.045 (just move the decimal 2 places left)
275*.045= 12.375  Susan gets $12.375 a year (don't round yet)
Multiply $12.375 by 5years          12.375*5= 61.875 (now round)
$61.90=B
I hope this helps! :)

5 0
4 years ago
The volume V of an ice cream cone is given by V = 2 3 πR3 + 1 3 πR2h where R is the common radius of the spherical cap and the c
Nuetrik [128]

Answer:

The change in volume is estimated to be 17.20 \rm{in^3}

Step-by-step explanation:

The linearization or linear approximation of a function f(x) is given by:

f(x_0+dx) \approx f(x_0) + df(x)|_{x_0} where df is the total differential of the function evaluated in the given point.

For the given function, the linearization is:

V(R_0+dR, h_0+dh) = V(R_0, h_0) + \frac{\partial V(R_0, h_0)}{\partial R}dR + \frac{\partial V(R_0, h_0)}{\partial h}dh

Taking R_0=1.5 inches and h=3 inches and evaluating the partial derivatives we obtain:

V(R_0+dR, h_0+dh) = V(R_0, h_0) + \frac{\partial V(R_0, h_0)}{\partial R}dR + \frac{\partial V(R_0, h_0)}{\partial h}dh\\V(R, h) = V(R_0, h_0) + (\frac{2 h \pi r}{3}  + 2 \pi r^2)dR + (\frac{\pi r^2}{3} )dh

substituting the values and taking dx=0.1 and dh=0.3 inches we have:

V(R_0+dR, h_0+dh) =V(R_0, h_0) + (\frac{2 h \pi r}{3}  + 2 \pi r^2)dR + (\frac{\pi r^2}{3} )dh\\V(1.5+0.1, 3+0.3) =V(1.5, 3) + (\frac{2 \cdot 3 \pi \cdot 1.5}{3}  + 2 \pi 1.5^2)\cdot 0.1 + (\frac{\pi 1.5^2}{3} )\cdot 0.3\\V(1.5+0.1, 3+0.3) = 17.2002\\\boxed{V(1.5+0.1, 3+0.3) \approx 17.20}

Therefore the change in volume is estimated to be 17.20 \rm{in^3}

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Step-by-step explanation:

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