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Allisa [31]
3 years ago
8

What is the distance between (4,5) and (4,-3)?

Mathematics
2 answers:
vaieri [72.5K]3 years ago
8 0
Sqrt(((4)-(4))^2+((-3)-(5))^2
sqrt((4-4)^2+(-3-5)^2))
sqrt((0)^2+(-8)^2)
sqrt(0+64)
sqrt(64)
8
Bas_tet [7]3 years ago
7 0
8 is the distance between the two points
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Janet is retiring after working for a major department store for 20 years. The company offered her a flat retirement benefit of
12345 [234]

Answer:

$1000

Explanation:

If the employee has worked there for 20 years and for every year its 50 dollars. That would mean its 50x20 which eqauls 1000.

8 0
2 years ago
Order the amount of rain from least to greatest
babymother [125]

Answer:

1/5, 1/2, 3/4

Step-by-step explanation:

I just now this already from experience, but you could covert all of the fractions into a common denominator. For example use 20.

1/5 = 4/20

1/2 = 10/20

3/4 = 15/20

Then you just need to look at the numerators which 4,10,15 would be the order. And then make sure to convert to the original fractions making the final order be 1/5, 1/2, 3/4.

8 0
3 years ago
Which weighs more 5.2 g or 500 cg
valina [46]
5.2g weighs more because A handful of paper clips is 5.2 grams. A handful of push pins is 500 centigram a. Which handful weighs more? So 1c equals .o1 grams so isn't it 5.2 g compared to .05 grams which then means the paper clips are heavier?
4 0
3 years ago
(Will give Brainliest/5 Stars if correct answer)
tensa zangetsu [6.8K]
Answer: Choice D) 
The angle between the two vectors is approximately 71.6 degrees

----------------------------------------------
----------------------------------------------

Work Shown: 

Each time I write the word "dot" I mean "dot product". 

|u| = length of vector u
|u| = sqrt(u dot u)
|u| = sqrt(<8,4> dot <8,4>)
|u| = sqrt(8*8 + 4*4)
|u| = sqrt(64 + 16)
|u| = sqrt(80)
|u| = sqrt(16*5)
|u| = sqrt(16)*sqrt(5)
|u| = 4*sqrt(5)

-----------------------

|v| = length of vector v
|v| = sqrt(v dot v)
|v| = sqrt(<9,-9> dot <9,-9>)
|v| = sqrt(9*9 + (-9)*(-9))
|v| = sqrt(81+81)
|v| = sqrt(2*81)
|v| = sqrt(2)*sqrt(81)
|v| = sqrt(2)*9
|v| = 9*sqrt(2)

-----------------------

u dot v = <8,4> dot <9,-9>
u dot v = 8*9 + 4*(-9)
u dot v = 72-36
u dot v = 36

-----------------------

cos(theta) = (u dot v)/(|u|*|v|)
cos(theta) = (36)/(4*sqrt(5)*9*sqrt(2))
cos(theta) = (36)/(36*sqrt(10))
cos(theta) = 1/(sqrt(10))
cos(theta) = sqrt(10)/10
theta = arccos(sqrt(10)/10)
theta = 71.56505
which rounds to 71.6 when rounding to one decimal place (nearest tenth)

That's why the approximate answer is roughly 71.6 degrees

7 0
3 years ago
a 4-meter ladder leans up a wall the foot of the ladder is 2 meters away from the wall how far up the wall will the ladder reach
svlad2 [7]
The answer is 3.46 meters

You can get the answer by using the pythagorean theorem, since the ladder and the wall form a right triangle.

c^2 = a^2 + b^2
4^2 = 2^2 + b^2
16 = 4 + b^2
12 = b^2
b = sqrt(12) or 3.46 meters
7 0
3 years ago
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