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slega [8]
3 years ago
11

Whitch is the value of this expression when a=5 and k=-2

Mathematics
1 answer:
lana66690 [7]3 years ago
7 0

Answer:

25/9

Step-by-step explanation:

25/9

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Simplify and rationalize the expression.
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adoni [48]
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7 0
3 years ago
Read 2 more answers
Can you help me please?
Vilka [71]

100 ml of fruit squash

sum the parts of the ratio, that is 2 + 7 = 9 parts

divide 450 ml by 9 to find 1 part

1 part = \frac{450}{9} = 50 ml

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7 0
3 years ago
In a large school, it was found that 77% of students are taking a math class, 74% of student are taking an English class, and 70
Iteru [2.4K]

Answer:

0.81 = 81% probability that a randomly selected student is taking a math class or an English class.

0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class

Step-by-step explanation:

We solve this question working with the probabilities as Venn sets.

I am going to say that:

Event A: Taking a math class.

Event B: Taking an English class.

77% of students are taking a math class

This means that P(A) = 0.77

74% of student are taking an English class

This means that P(B) = 0.74

70% of students are taking both

This means that P(A \cap B) = 0.7

Find the probability that a randomly selected student is taking a math class or an English class.

This is P(A \cup B), which is given by:

P(A \cup B) = P(A) + P(B) - P(A \cap B)

So

P(A \cup B) = 0.77 + 0.74 - 0.7 = 0.81

0.81 = 81% probability that a randomly selected student is taking a math class or an English class.

Find the probability that a randomly selected student is taking neither a math class nor an English class.

This is

1 - P(A \cup B) = 1 - 0.81 = 0.19

0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class

6 0
3 years ago
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