Y > 2x - 3
3y - x ≤ 6
↓
y = 2x - 3
3y - x = 6
3(2x - 3) - x = 6
3(2x) - 3(3) - x = 6
6x - 9 - x = 6
6x - x - 9 = 6
5x - 9 = 6
<u> + 9 + 9</u>
<u>5x</u> = <u>15</u>
5 5
x = 3
y = 2x - 3
y = 2(3) - 3
y = 6 - 3
y = 3
(x, y) = (3, 3)
3.5 + 3.5 +9+9 = 25. ;) i gotchu again.
Answer:
the reference angle is given by 
sine = negative
cosine = positive
tangent = negative
Step-by-step explanation:
We have been given the angle 
The angle lies in Quadrant IV. Hence, in order to find the reference angle, we can subtract this angle with 
Therefore, the reference angle is given by
In Quadrant IV, cosine and secant functions are positive and rest trigonometric functions are negative.
Thus, we have
sine = negative
cosine = positive
tangent = negative
Answer:
D
Step-by-step explanation:
In order to solve this we need to plug in the answer choices and make sure they work for BOTH answers!
Let us start with option A. (6,3) 3 = 4(6) + 6 = 3 = 30 This is automaticly wrong because 3 doesnt equal 30. There is no need to try it on the second equation since the first one was wrong.
Next answer choice, B (3,6) 6 = 2(3) = 6=6. The second equation works perfect for this. Now we have to make sure that it works for the first one as well. 6 = 4(3) + 6 = 6 = 18 which is wrong.
Next, C. (1,2) 2 = 2(1) = 2=2 Right now lets check the other equation.
2 = 4(1) + 6 = 2=10. Wrong
Last, D. (-3, -6) -6 = 2(-3) = -6 = -6 Right now lets check the other equation.
-6 = 4(-3) + 6 = -6 = -6. CORRECT. Answer choice D works for both equations.
Sorry for the wait of response.
