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madreJ [45]
3 years ago
10

hena made a table to show the steps and algebraic properties used to write an equivalent expression for 3 x minus 5 + 7 x + 6. S

tep Expression3 x minus 5 + 7 x + 6 Property 1 3 x + 7 x + 6 minus 5 Commutative property 2 (3 x + 7 x) + (6 minus 5) Distributive property 3 (3 + 7) x + (6 minus 5) Distributive property 4 10 x + 1 Addition property What error did Shena make? Shena should have written the associative property for step 1. Shena should have written the associative property for step 2. Shena should have written the associative property for step 3. Shena should have written the associative property for step 4.
Mathematics
1 answer:
Tcecarenko [31]3 years ago
3 0

Answer:

2.  Shena should have written the associative property for step 2.

Step-by-step explanation:

Trust me I just took this quiz on 202 edge and made a 100%

I hope this helps you :)

<em><u>-KeairaDickson</u></em>

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a 34 gram sample of a substance that's used to treat thyroid disorders has a k-value of 0.137. find the substance's half-life, i
Ira Lisetskai [31]

Answer:

5.1 days

Step-by-step explanation:

Given in the question,

initial amount of substance = 34 grams

k-value = 0.137

To find the half life of this substance we will use following formula

N(0)/2 = N(0)e^{-kt}

here N(0) is initial amount of substance

        t is time in days

Plug values in the formula

34 /2 = 34e^{-0.137t}

1/2 = e^{-0.137t}

Take logarithm on both sides

ln(1/2) = ln( e^{-0.137t})

ln(1/2) = -0.137t

t = ln(1/2) / -0.137

t = 5.059

t ≈ 5.1 days (nearest to tenths)

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Which expression is a difference of two terms that is equivalent to 6z - 13
Ivan

Answer:7 that’s easy

Step-by-step explanation:

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3 years ago
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7. A number of minor automobile accidents occur at various high-risk intersections in Teton County despite traffic lights. The T
Anit [1.1K]

Answer:

Modification has not reduced the number of accidents.

Step-by-step explanation:

H_0: \mu\geq0\\H_a:\mu

                                 A  B  C   D   E   F  G   H

Before modification 5  7  6   4    8   9   8   10

After modification    3  7  7   0    4   6   8    2

Difference                -2 0  1   -4   -4   -3  0   -8

Mean of differences M_d = \frac{sum}{8}=\frac{2+0-1+4+4+3-0+8}{8}=2.5

Standard deviation of differences = \sqrt{\frac{\sum(x-\bar{x})^2}{n}}=2.9277

Formula of paired t test :

t=\frac{M_d}{\frac{s}{\sqrt{n}}}\\t=\frac{2.5}{\frac{2.9277}{\sqrt{8}}}\\t = 2.4152

Df = n-1 = 8-1 =7

t critical = t_{(df, \alpha)}=t_{7,0.01}=2.998

t critical> t calculated

So, We failed to reject null hypothesis

Hence modification has not reduced the number of accidents.

6 0
3 years ago
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