Answer:
Perron–Frobenius theorem for irreducible matrices. Let A be an irreducible non-negative n × n matrix with period h and spectral radius ρ(A) = r. Then the following statements hold. The number r is a positive real number and it is an eigenvalue of the matrix A, called the Perron–Frobenius eigenvalue.
11+i
that’s the answer hope it helps:)
Answer:
f(n) = 6n + 12
Step-by-step explanation:
There is a common difference in consecutive number of seats, that is
42 - 36 = 36 - 30 = 30 - 24 = 24 - 18 = 6
This indicates the sequence is arithmetic with nth term
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = 18 and d = 6 , then
f(n) = 18 + 6(n - 1) = 18 + 6n - 6 = 6n + 12
2n - 7 = 5n -10
-5n -5n
-3n - 7= -10
+7 +7
-3n = -3
-3/-3 -3/-3
n= 1