This is a typical radioactive decay problem which uses the general form:
A = A0e^(-kt)
So, in the given equation, A0 = 192 and k = 0.015. We are to find the amount of substance left after t = 55 years. That would be represented by A. The solution is as follows:
A = 192e^(-0.015*55)
<em>A = 84 mg</em>
Answer:
1/168
Step-by-step explanation:
First, solve for the numerator.
-5/7÷30
-5/7÷30/1
(use keep, change flip)
-5/7x1/30=-5/210
-5/210=-1/42
Now use keep change flip again
-1/42÷-4/1
-1/42*-1/4=1/168
Answer:
33, 49, and 21.
Step-by-step explanation:
its 33, 49, and 21
hope this helps
3.14 * 3 * 6 = 56.52 cubic inches. Hope this helps. :)
