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evablogger [386]

2 years ago

8

Latasha explores some passages in a cave. The elevations of the passages are all above - 10 meters. Let y be the elevation of a

passage in meters. Write an inequality that represents elevations above -10 meters.

2 answers:

mojhsa [17]2 years ago

3 0

Answer:

Is this pure maths cause I don't know what's going on here

Tatiana [17]2 years ago

3 0

Answer:

It is y>-10

Step-by-step explanation:

i did it and i got it right.

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F incenter hope this helps

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3 years ago

What is multiplication

yawa3891 [41]

<h2>Answer:</h2>

A way of adding numbers. Contrast to division.

<h2>Step-by-step explanation:</h2>

Multiplication is when you have a number that you need to multiply by that number. Okay, let me give you an example:

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3 years ago

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11Alexandr11 [23.1K]

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3 0

6 months ago

Let x denote the lifetime of a mcchine component with an exponential distribution. The mean time for the component failure is 25

aliina [53]

Answer:

0.1353 = 13.53% probability that the lifetime exceeds the mean time by more than 1 standard deviations

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \mu e^{-\mu x}$

In which $\mu = \frac{1}{m}$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\mu x}$

The probability of finding a value higher than x is:

$P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}$

The mean time for the component failure is 2500 hours.

This means that $m = \frac{2500}, \mu = \frac{1}{2500} = 0.0004$

What is the probability that the lifetime exceeds the mean time by more than 1 standard deviations?

The standard deviation of the exponential distribution is the same as the mean, so this is P(X > 5000).

$P(X > x) = e^{-0.0004*5000} = 0.1353$

0.1353 = 13.53% probability that the lifetime exceeds the mean time by more than 1 standard deviations

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2 years ago

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3 years ago

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