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zysi [14]
4 years ago
6

SANDRA BIKED 800 METERS IN FRIDAY. ON SATURDAY, SHE BIKED 3 KILOMETERS. ON SUNDAY, SHE BIKED 2 KILOMETERS, 500 METERS. HOW MANY

KILOMETERS DID SANDRA BIKE OVER THE THREE DAYS?
Mathematics
1 answer:
stellarik [79]4 years ago
4 0

Answer:

1000 meters is 1 kilometer so...

At total he biked 6 kilometers, 200 meters

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What is 710-35w=570-25w
Vikentia [17]

Answer:

w=14

Step-by-step explanation:

Let's solve your equation step-by-step.

710−35w=570−25w

Step 1: Simplify both sides of the equation.

710−35w=570−25w

710+−35w=570+−25w

−35w+710=−25w+570

Step 2: Add 25w to both sides.

−35w+710+25w=−25w+570+25w

−10w+710=570

Step 3: Subtract 710 from both sides.

−10w+710−710=570−710

−10w=−140

Step 4: Divide both sides by -10.

−10w

−10

=

−140

−10

w=14

8 0
3 years ago
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ivolga24 [154]
I believe the answer is idk cause I’m not that smart
8 0
4 years ago
Read 2 more answers
ONCE I HIT 30 ILL GIVE YOU 100 Points if i get a good grade Maybe even more
N76 [4]

Answer:

The correct anwser is 2x+5<4

Step-by-step explanation:

8 0
3 years ago
In a local ice sculpture contest, one group sculpted a block into a rectangular based pyramid. The dimensions of the base were 3
masha68 [24]

Answer:

1. The amount of ice needed for the sculpture is 18 m³

2. The amount of fabric needed to manufacture the umbrella is 0.757 m²

3. The height of the cone is 37.5 cm

4. The largest possible storage area which is obtained by attaching the storage area to the back of the building is 87.11 m²

Step-by-step explanation:

1. The volume, V, of a rectangular pyramid = \dfrac{1}{3} \cdot B \cdot h

Where:

B = Base area = Length, L  × Width, W

h = Height of the pyramid = 3.6 m

L = 5 m

W = 3 m

The volume = 1/3 × 5 × 3 × 3.6 = 18 m³

The amount of ice needed for the sculpture is 18 m³

2) The surface area of a cone = π·r·s

s = Slant height

r = Radius of the cone's base = 0.4 m

h = The height of the cone = 0.45m

s = √(0.4² + 0.45²) = (√145)/20

The surface area of the cone = π × 0.4 × (√145)/20 = 0.757 m²

The amount of fabric needed to manufacture the umbrella is 0.757 m²

3) The volume, V of the cone = 150 cm³

The base area, A_b, of the cone = 12 cm²

The height of the cone = h

We note that the volume of a cone = \dfrac{1}{3} \cdot A_b \cdot h

Therefore;

\dfrac{1}{3} \times 12 \times  h = 150

4·h = 150

h = 150/4 = 37.5 cm

The height of the cone = 37.5 cm

4) The storage area at the back corner  with four sides = 100 m²

The storage area at the back of the building with three sides = 98 m²

Given that the available riling = 28 m, we have;

For maximum area the four sides should be equal, hence dimension of each side = 28/4 = 7

The area of storage space that can be fenced on four sides at the back corner = 7 × 7 = 49 m²

At the back of the building only three sides need fencing, we therefore have;

The side length = 28/3 = 9\frac{1}{3}

The area fenced = \left 9\frac{1}{3} \right  \times 9\frac{1}{3}  = 87\frac{1}{9} \ m^2 = 87.11 m²

Therefore, the largest possible storage area, 87.11 m², is obtained by attaching the storage area to the back of the building.

5 0
4 years ago
19. James has a desk job and would like to become more fit, so he purchases a
Neko [114]

Answer:

The correct answer is option (C)-0.245 = 2.160(0.205)

Step-by-step explanation:

Solution

Given that:

The slope = - 0.245

The size sample = n = 15

The standard error = 0.205

The confidence level = 95

The Significance level= α = (100- 95)% = 0.05

Now,

The freedom of degree = n-2 = 15 -2= 13

Thus,

the critical value = t* = 2.16

By applying Excel = [TINV (0.05, 13)]

The Margin of error is = t* (standard error)

=2.16 *0.205

= 0.4428

8 0
3 years ago
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